Hi,
I have created script which redirect the output to file.I am able to get the output in file but not in the format.
Output :Content of the log which have 10 -15 lines.
Actal :
Expected:
Please suggest how to make this.
Thanks,
Karthhik
Hello Karthik771,
Please use code tags as per forum rules for your codes/commands/Input_file which you are using into your posts. Your Input_file doesn't look in correct format may be you haven't pasted it correctly, if I am not wrong here you require space in between strings to be changed into new line. If this is the case then following may help you in same.
Also if above is not meeting your requirements then please use CODE TAGS and show us your correct sample for Input_file and expected output with all your conditions, I hope this helps you.
Hi,
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Discussion started by: braing
8 Replies
LEARN ABOUT PHP
escapeshellarg
ESCAPESHELLARG(3) 1 ESCAPESHELLARG(3)escapeshellarg - Escape a string to be used as a shell argumentSYNOPSIS
string escapeshellarg (string $arg)
DESCRIPTION escapeshellarg(3) adds single quotes around a string and quotes/escapes any existing single quotes allowing you to pass a string directly
to a shell function and having it be treated as a single safe argument. This function should be used to escape individual arguments to
shell functions coming from user input. The shell functions include exec(3), system(3) and the backtick operator.
On Windows, escapeshellarg(3) instead removes percent signs, replaces double quotes with spaces and adds double quotes around the string.
PARAMETERS
o $arg
- The argument that will be escaped.
RETURN VALUES
The escaped string.
EXAMPLES
Example #1
escapeshellarg(3) example
<?php
system('ls '.escapeshellarg($dir));
?>
SEE ALSO escapeshellcmd(3), exec(3), popen(3), system(3), backtick operator.
PHP Documentation Group ESCAPESHELLARG(3)