In my shell script i have a variable which stores date in the format of YYYYMMDD. Is there any way to format this value to MM/DD/YYYY.
Thanks. (8 Replies)
Hi All,
I have a string like below.
"Mar 31 2009" .
I want to convert this to unix time .
Also please let me know how to find the unix time for the above string minus one day. For Eg. if i have string "Mar 31 2009" i want to find the unix time stamp of "Mar 30 2009".
Thanks in advance,... (11 Replies)
Hello,
How do I convert unix timestamp value to 'normal' date format - to get year month and day values ?
Looks like it's easy to do using GNU date (linux systems). But how do I do tthis on AIX ?
I don't want to write C program, any ways to do that using unix shells ?
thanks (1 Reply)
(Attention: Green PHP newbie !)
I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,... (6 Replies)
hello,
i have an AIX5.3 machine and i am writing a script to display some processes.
inside the script i want to get the time that the process starts and convert it to a unix timestamp.
is there a command that i can use to do that? i search the web but all i found is long scripts and it does... (4 Replies)
How can I convert any user inputted date into yyyy/mm/dd ?
For example user can input date one of the following 20120121 , 2012-01-21 ,01/21/2012,01/21/2012 etc
But I need to convert any of the date entered by user into yyyy/mm/dd (2012/01/2012). Any suggestion. Thanks in advance
this is... (1 Reply)
Hi All,
I have file like
“April 10, 2013”,”raj”
“April 29, 2013”,”raj1”
Output :
“2013/04/10”,”raj”
“2013/04/29”,”raj1”
Please help me how to do... (9 Replies)
Hello I have a file : file1.txt with the below contents :
237176 test1 test2 1442149024
237138 test3 test4 1442121300
237171 test5 test7 1442112823
237145 test9 test10 1442109600
In the above file fourth field represents the timestamp in Unix format.
I found a command which converts... (6 Replies)
How to convert mmm-yy to mm/dd/yyyy format in unix ?
example:
Jan-99 to 01/01/1999
Jan-00 to 01/01/2000
Jan-25 to 01/01/2025
Dec-99 to 01/12/1999
Dec-00 to 01/12/2000
Dec-25 to 01/12/2025
YY anything between 00-50 should be 2000-2050
YY anything between 51-99 should be 1951-1999
... (2 Replies)
Discussion started by: gksenthilkumar
2 Replies
LEARN ABOUT PHP
datetime.__construct
DATETIME.__CONSTRUCT(3) 1 DATETIME.__CONSTRUCT(3)DateTime::__construct - Returns new DateTime object
Object oriented style
SYNOPSIS
public DateTime::__construct NULL ([string $time = "now"], [DateTimeZone $timezone])
DESCRIPTION
Procedural style
DateTime date_create NULL ([string $time = "now"], [DateTimeZone $timezone])
Returns new DateTime object.
PARAMETERS
o $time
-A date/time string. Valid formats are explained in Date and Time Formats. Enter NULL here to obtain the current time when using
the $timezone parameter.
o $timezone
- A DateTimeZone object representing the timezone of $time. If $timezone is omitted, the current timezone will be used.
Note
The $timezone parameter and the current timezone are ignored when the $time parameter either is a UNIX timestamp (e.g.
@946684800) or specifies a timezone (e.g. 2010-01-28T15:00:00+02:00).
RETURN VALUES
Returns a new DateTime instance. Procedural style returns FALSE on failure.
ERRORS /EXCEPTIONS
Emits Exception in case of an error.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.0 | |
| | |
| | If $time contains an invalid date/time format, |
| | then an exception is now thrown. Previously an |
| | error was emitted. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.__construct(3) example
Object oriented style
<?php
try {
$date = new DateTime('2000-01-01');
} catch (Exception $e) {
echo $e->getMessage();
exit(1);
}
echo $date->format('Y-m-d');
?>
Procedural style
<?php
$date = date_create('2000-01-01');
if (!$date) {
$e = date_get_last_errors();
foreach ($e['errors'] as $error) {
echo "$error
";
}
exit(1);
}
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-01
Example #2
Intricacies of DateTime.__construct(3)
<?php
// Specified date/time in your computer's time zone.
$date = new DateTime('2000-01-01');
echo $date->format('Y-m-d H:i:sP') . "
";
// Specified date/time in the specified time zone.
$date = new DateTime('2000-01-01', new DateTimeZone('Pacific/Nauru'));
echo $date->format('Y-m-d H:i:sP') . "
";
// Current date/time in your computer's time zone.
$date = new DateTime();
echo $date->format('Y-m-d H:i:sP') . "
";
// Current date/time in the specified time zone.
$date = new DateTime(null, new DateTimeZone('Pacific/Nauru'));
echo $date->format('Y-m-d H:i:sP') . "
";
// Using a UNIX timestamp. Notice the result is in the UTC time zone.
$date = new DateTime('@946684800');
echo $date->format('Y-m-d H:i:sP') . "
";
// Non-existent values roll over.
$date = new DateTime('2000-02-30');
echo $date->format('Y-m-d H:i:sP') . "
";
?>
The above example will output something similar to:
2000-01-01 00:00:00-05:00
2000-01-01 00:00:00+12:00
2010-04-24 10:24:16-04:00
2010-04-25 02:24:16+12:00
2000-01-01 00:00:00+00:00
2000-03-01 00:00:00-05:00
SEE ALSO DateTime.createFromFormat(3), DateTimeZone.__construct(3), Date and Time Formats, date.timezone ini setting, date_default_time-
zone_set(3), DateTime.getLastErrors(3), checkdate(3).
PHP Documentation Group DATETIME.__CONSTRUCT(3)