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To convert a date(in string format) to unix timestamp


 
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# 1  
Old 09-04-2009
To convert a date(in string format) to unix timestamp

Hi All,
I have a string like below.
"Mar 31 2009" .
I want to convert this to unix time .

Also please let me know how to find the unix time for the above string minus one day. For Eg. if i have string "Mar 31 2009" i want to find the unix time stamp of "Mar 30 2009".

Thanks in advance,
Giri

---------- Post updated at 05:36 AM ---------- Previous update was at 04:56 AM ----------

Can anyone please respond for this ?
Thanks,
Giri
# 2  
Old 09-04-2009
date -d "Mar 31 2009"
# 3  
Old 09-04-2009
Hi Siba,
I tried using the command provided by you, but error outs with the below error mesage.
date: Not a recognized flag: d
Usage: date [-u] [+"Field Descriptors"]

Kindly help .

Thanks,
Giri
# 4  
Old 09-04-2009
Which flavour of unix you are using?
# 5  
Old 09-04-2009
I use AIX and my shell is ksh.
# 6  
Old 09-04-2009
MySQL

If you know the date then just use..

echo "Mar 31 2009" | awk '{print $1 " " $2-1 " " $3}'

or else to print yesterday's date use...

date | awk '{print $3-1 " " $2 " " $6}'
# 7  
Old 09-04-2009
Hi abovais,

I tried with the below command provided by you,
echo "Mar 31 2009" | awk '{print $1 " " $2-1 " " $3}'

Its gives me "Mar 30 2009" . Now i want to convert this string to unix time. Kindly help me.
Thanks in advance,
Giri.

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