Hello
I need to write a shell script to update properties between files.
I have 2 files as follow:
file1
urlWebserviceCheckAddress^=McoConfigGlobal.commonGLOBALUrlWebservice
file 2
urlWebserviceCheckAddress=http://localhost:8080/tags
Both files containt the same properties... (1 Reply)
-Hi, I have several hundred files, which contain the following pattern:
/bb/bin/msga/mm 80&
I need to change the above pattern to be
/bb/bin/mm 80&
I there the command I can use to do that. Thanks a lot (3 Replies)
hi all,
Please help me with rsync.
I configured rsync to preserve timestamps using the -a option.
When i renamed fileA to fileB on source machine I have to copies at the backup server.
The aim is to keep the most recent file.
fileA & fileB has same contents.
When i renamed fileB to... (2 Replies)
Right I have a MYSQL database with table1 with 3 columns, colA, colB and colC. I want to combine the data in the 3 columns into a 4th column names col_comb. Here's the SQL command that works:
UPDATE table1 SET `col_comb` = CONCAT( `colA` , ' - ', `colB` , ', ', `colC` );
So now I want this... (5 Replies)
In the perl below I am trying to set/update the value of $14 (last field) in file2, using the matching NM_ in $12
or $9 in file2 with the NM_ in $2 of file1.
The lengths of $9 and $12 can be variable but what is consistent is the start pattern will always be NM_ and the end pattern is always
;... (4 Replies)
In the awk below I am trying to add a penalty to a score to each matching $1 in file2 based on the sum of $3+$4 (variable TL) from file1. Then the $4 value in file1 is divided by TL and multiplied by 100 (this valvue is variable S). Finally, $2 in file2 - S gives the updated $2 result in file2.... (2 Replies)
Dears,
I have a listfile contains list of files path.
i need to read the line of the listfile
mv the file to other directory
and update the listfile by deleting the lines of the listfile.
#!/bin/bash
target=/fstest/INVESTIG/Sadiq/TEST_ARCH
while read -r line || ];
do
mv $line... (19 Replies)
In the awk below I am trying to cp and paste each matching line in f2 to $3 in f1 if $2 of f1 is in the line in f2 somewhere. There will always be a match (usually more then 1) and my actual data is much larger (several hundreds of lines) in both f1 and f2. When the line in f2 is pasted to $3 in... (4 Replies)
Discussion started by: cmccabe
4 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)