Passing variable as input & storing output in other variable
I have a below syntax its working fine...
Im getting expected output as below:
Now I wrote a while loop.. the output of VAR12 should be passed as input parameters to while loop and results to be stored in a variable called as logdata
now my aganda is to store the output in a variables instead of storing output in a file. I have created a code but I m getting unexpected results & since last 2hrs I got stuck up with this
Last edited by Don Cragun; 09-06-2015 at 11:47 AM..
Reason: Change PHP tags to CODE tags.
HI
I am trying to store the output of this awk command
awk -F, {(if NR==2) print $1} test.sr
in a variable when I am trying v= awk -F, {(if NR==2) print $1} test.sr
$v = awk -F, {(if NR==2) print $1} test.sr
but its not working out .
Any suggestions
Thanks
Arif (3 Replies)
Hi unix gurus,
I am trying to store the result of a command into a variable.
But it is not getting stored.
x='hello'
y=echo $x | wc -c
but it is giving the output as 0(zero)
Pls help me its very urgent (7 Replies)
Hi all,
I'm creating a script which uses 'defaults read' to retrieve details from an Info.plist like this;
defaults read "/Path/Contents/Info" CFBundleShortVersionString
This works fine in Terminal and returns the expected values.
Is it possible to use this command in a script, and... (0 Replies)
Hi,
i have some files in one directory(say some sample dir) whose names will be like the following.
some_file1.txt
some_file2.txt.
i need to get the last modified file size based on file name pattern like some_
here i am able to get the value of the last modified file size using the... (5 Replies)
I'm sure this is a simple thing but I can't figure it out. In a script that I'm writing, I'd like to be able to store each line of output from "ls -l" into a variable. Ultimately I'd like to end up with something like:
for a in `ls -l`
do something with $a
doneBut that's reading each... (2 Replies)
Hi All,
Hope someone can advise here as I have been struggling to find a syntax that works here. I have tried a stack of combination I have seed in the forums but I think because I have needed to use "" and `` in the statments another method is found.
I am reading in lines with the following... (1 Reply)
Hi!
i'm trying to parse textfiles against a pattern and storing the result in a variable.
The strings i want to get are embraced by and can occur several times in one line, so e.g.
some text anything else endwhat i have so far:
#!/bin/bash
for f in $*
do
exec 3<&0
exec 0<$f
... (2 Replies)
Hey guys got a slight problem here, I kindda new to socket programming in C so I need some guide on how to store something like this in a variable.
printf ("%s Name : %s\n", id,getNAME(name));
name is declared as name.
The getName is a function.
So what I'm... (7 Replies)
My script below seems to be choking because I need the the output of the find command to be stored as a variable that can then be called by used lower in the script.
#!/bin/bash
cd "/resumes_to_be_completed"
var1=find . -mmin -1 -type f \( -name "*.doc" -o -name "*.docx" \)... (1 Reply)
Hi,
My aim is to get the md5 hash of a file and store it in a variable.
var1="md5sum file1"
$var1
The above outputs fine but also contains the filename, so somthing like this 243ASsf25 file1
i just need to get the first part and put it into a variable.
var1="md5sum file1"... (5 Replies)
Discussion started by: JustALol
5 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)