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Full Discussion: Create dynamical from files in directory
Top Forums Shell Programming and Scripting Create dynamical from files in directory Post 302947706 by Scrutinizer on Saturday 20th of June 2015 06:08:44 PM
Old 06-20-2015
Try something like:
Code:
select f in $(ls -p | grep -v /)
do
  cat "$f"
done

This would only work if the are no files with spaces or newlines in the directory which may be OK from the command line..

A more robust solution - using bash arrays - would be:

Code:
files=(*)
for ((i=0; i<${#files[@]}; i++))
do
  [ -f "${files[i]}" ] || unset files[i]      # remove directory entries that are not plain files
done

select f in "${files[@]}"; 
do 
  cat "$f"
done

Last edited by Scrutinizer; 06-20-2015 at 08:33 PM..
This User Gave Thanks to Scrutinizer For This Post:
kl1ngac1k
 

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LEARN ABOUT PHP

zgrep

ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep	options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

																	  ZGREP(1)
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