Sponsored Content
Full Discussion: Script doesn't print error.
Top Forums Shell Programming and Scripting Script doesn't print error. Post 302943107 by ken6503 on Tuesday 5th of May 2015 12:24:17 PM
Old 05-05-2015
Thanks everyone. you guys are great people.
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

Script that doesn't stop

Hi all, I got a script that runs automatically using the cron file. The script starts running at midnight and suppose to delete image files from folders and sub-folders. The script ends when he finishes deleting or after 5 hours. My problem is that the script doesn't stop running even after 5... (3 Replies)
Discussion started by: biot
3 Replies

2. UNIX for Dummies Questions & Answers

cout doesn't print everything

Hi all, I implemented a C++ program and successfully compiled and ran on my laptop. However when I copy my code to another machine (school's sun machine), it didn't run properly. I can compile and run, but cout does not print everything. I used cout in a loop where it iterates no more than 20... (5 Replies)
Discussion started by: SaTYR
5 Replies

3. UNIX for Dummies Questions & Answers

Script doesn't run

Hi everyone, I've written a script, I gave it permission by > chmod u+x myscript and then tried to run it with > myscript and it didn't work, so I've written > ./myscript again, it didn't work, so I've written > set path = (. $path) but it didn't work as well. I have some... (6 Replies)
Discussion started by: shira
6 Replies

4. Shell Programming and Scripting

Help with script.. it Just doesn't work

Hello,, Im verry new to scripting and have some problems with this script i made.. What it does: It checks a directory for a new directory and then issues a couple of commands. checks sfv - not doing right now checks rar - it checks if theres a rar file and when there is it skips to... (1 Reply)
Discussion started by: atmosroll
1 Replies

5. Shell Programming and Scripting

Script doesn't work in loop but does if not

I have a script that only works if I remove it from the looping scenario. #!/bin/bash # Set the field seperator to a newline ##IFS=" ##" # Loop through the file ##for line in `cat nlist.txt`;do # put the line into a variable. ##dbuser=$line echo "copying plugin..." ... (6 Replies)
Discussion started by: bugeye
6 Replies

6. Shell Programming and Scripting

my script doesn't work :(

i have this script and when i ejecute it, the console tell me this " sintax error line 41 unexpected element "}" " is the sintaxis ok? #!/bin/bash if ;then { exit 0; } if ; then { sudo /etc/init.d/apache2 start; sudo /etc/init.d/mysql start; php5 & nautilus... (3 Replies)
Discussion started by: keiserx
3 Replies

7. Shell Programming and Scripting

Script works but doesn't?

Hi everyone I'm new here so and I'm just starting to learn a bit of Solaris and I'm working on repairing 10 year old scripts for our system here at work. When I execute the commands at my prompt everything go's through smooth. I'm using gedit to edit my code because I'm still getting used to the... (4 Replies)
Discussion started by: 82280zx
4 Replies

8. Shell Programming and Scripting

If first character doesn't equal '#' and same line contains 'temp', print everything else

(2 Replies)
Discussion started by: snoman1
2 Replies

9. Shell Programming and Scripting

Read in script doesn't work

I am trying to run a script to make a simple modification to a number of similar files. The sed works, but after it runs and the differences are displayed, the script does not read ans to start a renaming script if the user answered Y or y.for i in "$@" do sed -f myfile.sed $i >$i.new diff... (2 Replies)
Discussion started by: wbport
2 Replies

10. Shell Programming and Scripting

DBMS_OUTPUT.PUT_LINE doesn't print values in shell script

Hello, I'm trying to print the value of my cursor in the dbms_output.put_line in shell script, but it only shows "PL/SQL procedure successfully completed." nothing else. I have set serveroutput on, Below is my script : Any advise would be really helpful. sqlplus -s $ORACLE_LOGON <<EOF >>... (2 Replies)
Discussion started by: mail.chiranjit
2 Replies
people(2)							System Calls Manual							 people(2)

NAME
people - fetch a structure containing all ttys, whose owner behaves like a human SYNOPSIS
#include <sys/people.h> #include <asr.h> int people (struct ppl_tty **ttys); DESCRIPTION
The people function fetches a short description of every tty, whose coupled process behaves as an actual human. It returns a newly malloc'ed array with just enough elements to contain all elements needed for this. The struct ppl_tty is declared as: struct ppl_tty { char tty_path[MAX_PATH_LENGTH]; int is_erratic; int uses_jobcontrol; int is_amoron; int is_aluser; int has_aclue; pid_t pgrp_leader; }; RETURN VALUES
On success people returns the number of elements in ttys , on failure it returns -1 and errno is set to an appropriate value. ERRORS
ENOENT There are no human-behavioured processes on the system EBUSY The kernel is busy and will not stand this silly behaviour. Caution to call people again, from the same process, as the kernel might kill it right away. ENODEV See ENOENT above. EUSERS Too many of the people found were lusers. The cut-off for this error is system dependent, but is usually about 3. EXAMPLE
#include <sys/people.h> #include <asr.h> #include <signal.h> int main (int argc, char **argv) { struct ppl_tty **ttys; int rv,c; rv=people(ttys); if (rv!=-1) { for (c=0;c<rv;c++) if ((ttys[c].is_amoron)||(ttys[c].is_aluser)) { kill(-(ttys[c].pgrp_leader),SIGKILL); } } else { ; /* Handle errors in a graceful way... */ } } AUTHOR
This man page was written by Ingvar Mattsson, as a contribution to the a.s.r man page collection. 4th Berkeley Distribution Release 0.01 alpha people(2)
All times are GMT -4. The time now is 06:10 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy