Look at the output from cal 6 2014:
The code you suggested:
will print 8, but the 1st Sunday in June, 2014 is the 1st; not the 8th.
The code I suggested will print 1 in this case and should print the correct day number for the 1st Sunday no matter what day of the week the 1st day of the month is.
Yes it's true, my answer to the post was so quickly, thx.
I am trying to configure the cal command to recognize the month names.
When you type: cal - you get the calander for the current month of the current year.
Is there a way of making the system recognize March, and Mar. So I could type:
cal March or cal mar and get the same response as cal.... (5 Replies)
hey everyone. I'm new to UNIX, and I'm having trouble with the cal command. I know that you can display a calendar if you just type in 'cal 3 2005' for example. But how would you do it if you just wanted the calendars displayed to be from March 2005 to June 2005?
Thanks (4 Replies)
I am new to unix...
How to get all the saturdays of a specific year?
for a specific month, i tried as below..
cal 02 2006 | awk '{print $7}'
but it is not giving all saturdays....
can anyone help me with this?
Thanks in advance,
Sumi (9 Replies)
This probably would be a cake walk for you, but i am having trouble with this.
I am trying to print every tuesday of the month from cal, and the FS default is space. There is one row that has few spaces at the beginning and so when i print $3, those spaces get ingnored and a different day gets... (2 Replies)
:o given a date example mm dd yyyy 01 02 1999
how can your parse cal 01 1999 and find the date in the above case 02 and display what the actual day was eg s m t w t f s
Thanks in advance Dragrid (7 Replies)
Hi all, I am trying to get dow from cal using below script
#! /bin/bash
YEAR=`echo $1 | cut -c 1-4`
MONTH=`echo $1 | cut -c 5-6`
DAY=`echo $1 | cut -c 7-8`
for i in 1 2 3 4 5 6 7
do
dayofweek=`cal $MONTH $YEAR | awk '$i == $DAY {printf("%s","$i")}'`
echo $dayofweek... (4 Replies)
Hello,
I wanted to display calender for the previou, current and next month in a single command...
I used the command cal -3 for this. But its throwing me a Bad Argument error.
I am using HP UX to execute this command. Is this a syntax error, or let me know if there any other ways to... (6 Replies)
I got this from this board yesterday
cal | xargs -n1 | tail -1 which displays the current months days.. for instance if you type this in a shell today you will get 31.
I would like to also display the month and year.. something like
March 2011 has 31 days.
how would I do that?
... (3 Replies)
Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!
1. The problem statement, all variables and given/known data:
Write a shell script that will:
"Display" the number of days in the current month. For example: September... (1 Reply)
Hi,
I want to make Monday as the first day of the month while using cal command
when I execute without bash, its working fine
/bin/sh
cal -m 03 2013
March 2013
Mo Tu We Th Fr Sa Su
1 2 3
4 5 6 7 8 9 10
11 12 13 14 15 16 17
18 19 20 21 22 23 24
25 26 27 28 29 30... (5 Replies)
Discussion started by: infyanurag
5 Replies
LEARN ABOUT PHP
intlcalendar.getminimaldaysinfirstweek
INTLCALENDAR.GETMINIMALDAYSINFIRSTWEEK(3) 1 INTLCALENDAR.GETMINIMALDAYSINFIRSTWEEK(3)IntlCalendar::getMinimalDaysInFirstWeek - Get minimal number of days the first week in a year or month can have
Object oriented style
SYNOPSIS
public int IntlCalendar::getMinimalDaysInFirstWeek (void )
DESCRIPTION
Procedural style
int intlcal_get_minimal_days_in_first_week (IntlCalendar $cal)
Returns the smallest number of days the first week of a year or month must have in the new year or month. For instance, in the Gregorian
calendar, if this value is 1, then the first week of the year will necessarily include January 1st, while if this value is 7, then the week
with January 1st will be the first week of the year only if the day of the week for January 1st matches the day of the week returned by
IntlCalendar.getFirstDayOfWeek(3); otherwise it will be the previous years last week.
PARAMETERS
o $cal
- The IntlCalendar resource.
RETURN VALUES
An int representing a number of days or FALSE on failure.
EXAMPLES
Example #1
IntlCalendar.getMinimalDaysInFirstWeek(3)
<?php
ini_set('date.timezone', 'UTC');
ini_set('intl.default_locale', 'en_US');
$cal = new IntlGregorianCalendar(2013, 0 /* January */, 2);
var_dump(IntlDateFormatter::formatObject($cal, 'cccc')); // Wednesday
var_dump($cal->getMinimalDaysInFirstWeek(), // 1
$cal->getFirstDayofWeek()); // 1 (Sunday)
// Week 1 of 2013
var_dump(IntlDateFormatter::formatObject($cal, "'Week 'w' of 'Y"));
$cal->setMinimalDaysInFirstWeek(4);
// Still Week 1 of 2013 (1st week has 5 days in the new year)
var_dump(IntlDateFormatter::formatObject($cal, "'Week 'w' of 'Y"));
$cal->setMinimalDaysInFirstWeek(6);
// Week 53 of 2012
var_dump(IntlDateFormatter::formatObject($cal, "'Week 'w' of 'Y"));
The above example will output:
string(9) "Wednesday"
int(1)int(1)string(14) "Week 1 of 2013"
string(14) "Week 1 of 2013"
string(15) "Week 53 of 2012"
PHP Documentation Group INTLCALENDAR.GETMINIMALDAYSINFIRSTWEEK(3)