awk to print the line that matches and the next if line is wrapped
I have a file and when I match the word "initiators" in the first column I need to be able to print the rest of the columns in that row. This is fine for the most part but on occasion the "initiators" line gets wrapped to the next line. Here is a sample of the file.
How do I print the initiator info when it is matched in the 2nd instance above? I would like the ouput to be like this.
---------- Post updated at 11:43 AM ---------- Previous update was at 11:04 AM ----------
I am able to extract the info I need but I want it to print on the same line. I am using
And this gets me the output in this format.
But I want it to output in the following format
---------- Post updated at 12:02 PM ---------- Previous update was at 11:43 AM ----------
Seems like a roudabout way to do it but I got it working by using the following command. Alternatives are welcome.
Hi
i need a help for making a script whch can print next line if it matches a particular word
like file1 have
ename Mohan
eid 2008
ename Shyam
eid 345
if scipt got Mohan it will print next line (eid 2008)
pls help me .......:) (2 Replies)
Hi All,
I would like my code to be able to print out the whole line if 1st field has a dot in the number. Sample input and expected output given below.
My AWK code is below but it can;t work, can any expert help me ?
Thanks in advance.
{if ($1 ~ /*\.*/) { print $0 }}
Input:
... (2 Replies)
Hi all,
I got several lines line this
a b c d e 1 e
a 1 c d e 3 f
a b c 1 e 8 h
a b c d e 1 w
a 1 c d e 2 w
a b c d e 1 t
a b c d e 7 4
How can I print the line if 1 is the field one before the last field?
Basicly this 2 field ?
a b c d e 1 e
a b c d e 1 t
The file I got is... (7 Replies)
Hi Folks!
im printing all lines where the characters in position 270-271 match 33|H1|HA|KA|26 so i came up with this
#!/bin/bash
array=(33 H1 HA KA 26 )
for i in "${array}"
do
#echo $i
awk '{ if (substr($0,270,2)~'/$i/') print; }' $1 >> $1.temp
done
It works fine . but... (2 Replies)
I'm using sh on hp-ux and want to find / print a line that matches 132.101- and the next line, too. grep -A isn't supported on hp-ux, so I'm trying awk and sed.
The code below works but only prints the first occurence. I need all matches from the file.
awk... (2 Replies)
Good day,
I have a list of regular expressions in file1. For each match in file2, print the containing line and the line after.
file1:
file2:
Output:
I can match a regex and print the line and line after
awk '{lines = $0} /Macrosiphum_rosae/ {print lines ; print lines } '
... (1 Reply)
Hi,
I could only find examples to print line before/after a match, but I'd need to print line after two separate lines matching.
E.g.: From the below log entry, I would need to print out the 1234. This is from a huge log file, that has a lot of entries with "CLIENT" and "No" entries (+ other... (3 Replies)
Hi
I want to extend following command so that on the basis of "Branch: ****" on the third line I can grep and print name of the file on the first line.
cat .labellog.emd | grep DA2458A7962276A7E040E50A0DC06459 | cut -d " " -f2 | grep -v branch_name | xargs -I file <command to describe> file
... (1 Reply)
Der colleagues,
4 days I am trying to solve my issue and no success..
Maybe you can give me a clue how to achieve what I need..
So I have two files.
file1 example:
1_column1.1 1_column2.1 aaa 1_column4.1
1_column1.2 1_column2.2 ttt 1_column4.2
1_column1.3 1_column2.3 ... (10 Replies)