Sponsored Content
Top Forums Shell Programming and Scripting Sort based on certain value in a column Post 302899975 by redse171 on Friday 2nd of May 2014 04:29:15 PM
Old 05-02-2014
Hi jim mcnamara,

I just edited the filename in my question above as it seems confusing. Ok, the sample input is "input1.txt" and the sample output is "output.txt". Thanks
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Question about sort specific column and print other column at the same time !

Hi, This is my input file: ali 5 usa abc abu 4 uk bca alan 6 brazil bac pinky 10 utah sdc My desired output: pinky 10 utah sdc alan 6 brazil bac ali 5 usa abc abu 4 uk bca Based on the column two, I want to do the descending order and print out other related column at the... (3 Replies)
Discussion started by: patrick87
3 Replies

2. Shell Programming and Scripting

sort on second column only based on first column

I have an input file like this... AAAlkalines Energizer AAAlkalines Energizer AAAlkalines Energizer AAAlkalines Sunlight AAAlkalines Sunlight AAAlkalines Sunlight AAAlkalines Energizer AAAlkalines Energizer AAAlkalines Energizer AAASalines ... (7 Replies)
Discussion started by: malcomex999
7 Replies

3. Shell Programming and Scripting

Sort file based on column

Hi, My input file is $cat samp 1 siva 1 raja 2 siva 1 siva 2 raja 4 venkat i want sort this name wise...alos need to remove duplicate lines. i am using cat samp|awk '{print $2,$1}'|sort -u it showing raja 1 (3 Replies)
Discussion started by: rsivasan
3 Replies

4. UNIX for Dummies Questions & Answers

How to sort a column based on numerical ascending order if it includes e-10?

I have a column of numbers in the following format: 1.722e-05 2.018e-05 2.548e-05 2.747e-05 7.897e-05 4.016e-05 4.613e-05 4.613e-05 5.151e-05 5.151e-05 5.151e-05 6.1e-05 6.254e-05 7.04e-05 7.12e-05 7.12e-05 (6 Replies)
Discussion started by: evelibertine
6 Replies

5. UNIX for Dummies Questions & Answers

Sort command in one column and not effect to another column

If my data is numerical : 1 = 101 2 = 102 3 = 104 4 = 104 7 = 103 8 = 103 9 = 105 I need the result like below: 1 = 101 2 = 102 3 = 103 4 = 103 7 = 104 8 = 104 9 = 105 (4 Replies)
Discussion started by: GeodusT
4 Replies

6. Shell Programming and Scripting

Sort based on column 1, not working with awk

Hi Guru, I need some help regarding awking the output so it only show the first line (based on column) of each row. So If column has 1, three row, then it only show the first line of that row, based on similar character in column 1. So i am trying to achieve a sort, based on column one and... (3 Replies)
Discussion started by: Junes
3 Replies

7. Shell Programming and Scripting

Sum column values based in common identifier in 1st column.

Hi, I have a table to be imported for R as matrix or data.frame but I first need to edit it because I've got several lines with the same identifier (1st column), so I want to sum the each column (2nd -nth) of each identifier (1st column) The input is for example, after sorted: K00001 1 1 4 3... (8 Replies)
Discussion started by: sargotrons
8 Replies

8. UNIX for Beginners Questions & Answers

How to align/sort the column pairs of an csv file, based on keyword word specified in another file?

I have a csv file as shown below, xop_thy 80 avr_njk 50 str_nyu 60 avr_irt 70 str_nhj 60 avr_ngt 50 str_tgt 80 xop_nmg 50 xop_nth 40 cyv_gty 40 cop_thl 40 vir_tyk 80 vir_plo 20 vir_thk 40 ijk_yuc 70 cop_thy 70 ijk_yuc 80 irt_hgt 80 I need to align/sort the csv file based... (7 Replies)
Discussion started by: dineshkumarsrk
7 Replies

9. Shell Programming and Scripting

Use sort to sort numerical column

How to sort the following output based on lowest to highest BE? The following sort does not work. $ sort -t. -k1,1n -k2,2n bfd.txt BE31.116 0s 0s DOWN DAMP BE31.116 0s 0s DOWN DAMP BE31.117 0s 0s ... (7 Replies)
Discussion started by: sand1234
7 Replies

10. UNIX for Beginners Questions & Answers

Sort based on one column

Hi All , I am having an input file like this Input file 7 sks/jsjssj/ddjd/hjdjd/hdhd/Q 10 0.5 13 dkdkd/djdjd/djdjd/djd/QB 01 0.5 ldld/dkd/jdf/fjfjf/fjf/Q 0.5 10 sjs/jsdd/djdkd/dhd/Q 01 0.5 21 kdkd/djdd/djdd/jdd/djd/QB 01 0.5 dkdld/djdjd/djd/Q 01 0.5 ... (9 Replies)
Discussion started by: kshitij
9 Replies
bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
All times are GMT -4. The time now is 10:18 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy