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How to sort a column based on numerical ascending order if it includes e-10?

 
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# 1  
Old 07-06-2011
How to sort a column based on numerical ascending order if it includes e-10?
I have a column of numbers in the following format:


1.722e-05
2.018e-05
2.548e-05
2.747e-05
7.897e-05
4.016e-05
4.613e-05
4.613e-05
5.151e-05
5.151e-05
5.151e-05
6.1e-05
6.254e-05
7.04e-05
7.12e-05
7.12e-05

I want to sort it in numerical ascending order but the e-'s complicate things. How do I go about doing this? Thanks!
# 2  
Old 07-06-2011
I'm not sure, this is what you want. Just try this,

Code:
sort -k1 <Input filename>

O/P:
PHP Code:
1.722e-05
2.018e-05
2.548e-05
2.747e-05
4.016e-05
4.613e-05
4.613e-05
5.151e-05
5.151e-05
5.151e-05
6.1e-05
6.254e-05
7.04e-05
7.12e-05
7.12e-05
7.897e-05 
# 3  
Old 07-06-2011
Code:
$ sort -k1,1g test.txt 
1.722e-05
2.018e-05
2.548e-05
2.747e-05
4.016e-05
4.613e-05
4.613e-05
5.151e-05
5.151e-05
5.151e-05
6.1e-05
6.254e-05
7.04e-05
7.12e-05
7.12e-05
7.897e-05

# 4  
Old 07-06-2011
Thanks but both solutions fail since there are both e-05's and e-06's in the document:

Example:


13 rs9528959 6.583e-06
13 rs7981715 6.525e-05
13 rs7338191 1.336e-05
13 rs4432150 2.861e-06
13 rs4337178 5.039e-05
13 rs1578307 2.861e-06
13 rs12876335 2.638e-06
# 5  
Old 07-06-2011
if you want to sort the third column, the use 3,3
# 6  
Old 07-06-2011
You can do it all in awk by writing a sorting routine or an awk sort awk pipeline...
Code:
awk '{printf("%.20f\n",$0)}' file | sort -nk1,1 | awk '{printf("%e\n",$0)}'

# 7  
Old 07-06-2011
Quote:
Originally Posted by itkamaraj
Code:
$ sort -k1,1g test.txt 
1.722e-05
2.018e-05
2.548e-05
2.747e-05
4.016e-05
4.613e-05
4.613e-05
5.151e-05
5.151e-05
5.151e-05
6.1e-05
6.254e-05
7.04e-05
7.12e-05
7.12e-05
7.897e-05

Hi.
I know the -k1 meaning?
Could you explain 1g?
Thanks a lot
 
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