I want to grep a range of numbers in a log file. My log file looks like this:
20050807070609Z;blah blah
That is a combination of yr,month,date,hours,minutes,seconds.
I want to search in the log file events that happened between a particular time.
like between 20050807070000 to 20050822070000... (1 Reply)
Hi im new to unix and need to find a way to grep the top 5 numbers in a file and put them into another file. For example my file looks like this
abcdef 50000
abcdef 45000
abcdef 40000
abcdef 35000
abcdef 30000
abcdef 25000
abcdef 20000
abcdef 15000
abcdef 10000
and so on...
How can... (1 Reply)
Howdy experts,
We have some ranges of number which belongs to particual group as below.
GroupNo StartRange EndRange
Group0125 935300 935399
Group2006 935400 935476
937430 937459
Group0324 935477 935549
... (6 Replies)
if the column1 and 2 in both files has same key (for example "a" and "a1") compare each first key value(a1 of a) of input2 (for example 1-4 or 65-69 not 70-100 or 44-40 etc) with all the values in input1.
if the range of first key value in input2 is outof range in input1 values named it as out... (54 Replies)
Hello,
I have a column where there are values from 1 to 150.
I want to get the frequency of values in the following ranges:
1-5
6-10
11-15
....
....
....
146-150
How can I do this in a for loop?
Thanks,
Guss (1 Reply)
Dear Friends,
I want to know how to grep for the lines that has a number between given range(start and end).
I have tried the following sed command.
sed -n -e '/20030101011442/,/20030101035519/p'
However this requires both start and end to be part of the content being grepped. However... (4 Replies)
I am trying to extract specific information from a large *.sam file (it's originally 28Gb).
I want to extract all lines that are on chr3 somewhere in the range of 112,937,439-113,437,438.
Here is a sample line from my file so you can get a feel for what each line looks like:
seq.4 0 ... (8 Replies)
Hi
I am getting an argument which specifies the range of numbers. eg: 7-15
Is there a way that i can easily (avoiding loop) print the range of number between and including the specified above.
The above example should translate to 7,8,9,10,11,12,13,14,15 (3 Replies)
Discussion started by: tostay2003
3 Replies
LEARN ABOUT PLAN9
grep
GREP(1) General Commands Manual GREP(1)NAME
grep - search a file for a pattern
SYNOPSIS
grep [ option ... ] pattern [ file ... ]
DESCRIPTION
Grep searches the input files (standard input default) for lines (with newlines excluded) that match the pattern, a regular expression as
defined in regexp(6). Normally, each line matching the pattern is `selected', and each selected line is copied to the standard output.
The options are
-c Print only a count of matching lines.
-h Do not print file name tags (headers) with output lines.
-i Ignore alphabetic case distinctions. The implementation folds into lower case all letters in the pattern and input before interpre-
tation. Matched lines are printed in their original form.
-l (ell) Print the names of files with selected lines; don't print the lines.
-L Print the names of files with no selected lines; the converse of -l.
-n Mark each printed line with its line number counted in its file.
-s Produce no output, but return status.
-v Reverse: print lines that do not match the pattern.
Output lines are tagged by file name when there is more than one input file. (To force this tagging, include /dev/null as a file name
argument.)
Care should be taken when using the shell metacharacters $*[^|()= and newline in pattern; it is safest to enclose the entire expression in
single quotes '...'.
SOURCE
/sys/src/cmd/grep.c
SEE ALSO ed(1), awk(1), sed(1), sam(1), regexp(6)DIAGNOSTICS
Exit status is null if any lines are selected, or non-null when no lines are selected or an error occurs.
GREP(1)