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Full Discussion: Having a little trouble with grep
Top Forums Shell Programming and Scripting Having a little trouble with grep Post 302870435 by MadeInGermany on Sunday 3rd of November 2013 03:13:57 PM
Old 11-03-2013
Code:
ls -l | grep '^[l]'"$argv[1]"'$'

The shell sees 3 strings where the midle one is in " " i.e. allows variable substitution. grep sees one string without any quotes.
 

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LEARN ABOUT NETBSD

zgrep

ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME

     zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files

SYNOPSIS

     zgrep [grep-flags] [--] pattern [files ...]

     zegrep [grep-flags] [--] pattern [file ...]

     zfgrep [grep-flags] [--] pattern [file ...]

DESCRIPTION

     zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1).

     The grep-flags and pattern arguments are passed on to grep(1).  If an -e flag is found in the grep-flags, zgrep will not look for a pattern
     argument.

     zegrep calls egrep(1), while zfgrep calls fgrep(1).

EXIT STATUS

     In case of missing arguments or missing pattern, 1 will be returned, otherwise 0.

SEE ALSO

     egrep(1), fgrep(1), grep(1), gzip(1), zcat(1)

AUTHORS

     Thomas Klausner <wiz@NetBSD.org>

BSD
								 December 28, 2003							       BSD
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