Sponsored Content
Top Forums Shell Programming and Scripting Incrementing parts of ten digits number by parts Post 302862403 by ctsgnb on Thursday 10th of October 2013 04:29:07 PM
Old 10-10-2013
Please provide exactly the command line you've launched in the first run and in the second run.

By the way, the run i've tried with your code when i pass
Code:
2013080805

returns
Code:
201308086

Fyi you could use printf see :
Code:
$ i=6
$ echo $i
6
$ printf '%02d\n' $i
06
$

 

9 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

cksum parts of a file

Every time we build an executable the date and time are put into the file, I need to run checksum on just the working lines.(IE, no header files) Is this even possible, if so how would I go about it? I am using a HP-UX server any help you can give me will be greatly appreciated. Thanks (6 Replies)
Discussion started by: crazykelso
6 Replies

2. Shell Programming and Scripting

getting parts of a file

Hello, I'm trying to retreive certain bits of info from a file. the file contains a list like this info1:info2:info3:info4 info1:info2:info3:info4 info1:info2:info3:info4 info1:info2:info3:info4 how do i pick out only info2 or only info3 without the others? Thanks (11 Replies)
Discussion started by: bebop1111116
11 Replies

3. Shell Programming and Scripting

Extracting parts of a file.

Hello, I have a XML file as below and i would like to extract all the lines between <JOB & </JOB> for every such occurance. The number of lines between them is not fixed. Anyways to do this awk? ============ <JOB APR="1" AUG="1" DEC="1" FEB="1" JAN="1" JUL="1" JUN="1" MAR="1" MAY="1"... (3 Replies)
Discussion started by: srivat79
3 Replies

4. Shell Programming and Scripting

[ask]break line number into several parts

hlow all, i have file with wc -l file.txt is 3412112 line number so I want to break these files into several parts with assumsi line 1-1000000 will be create part1.txt and 1000001-2000000 will create part2.txt and 2000001-3000000 will create part3.txt and 3000001-3412112 will create... (5 Replies)
Discussion started by: zvtral
5 Replies

5. Shell Programming and Scripting

Parts is parts, but all together ...

I understand the individual pieces of the following (with one exception ..), but how does it all work as one? find ${HOME}/reports/ -name surveyresult*.txt -exec ls -1 {} \; | /usr/xpg4/bin/grep -E \ "${HOME}/reports/surveyresult{14,14}.txt" | sort > ${ResultsFileList} Find all files like... (1 Reply)
Discussion started by: jdorn001
1 Replies

6. Shell Programming and Scripting

Extract Parts of File

Hello All, I have a file like this Define schema flat_file_schema ( a varchar(20) ,b varchar(30) ,c varchar(40) ); (Insert into table ( a ,b ,c ) values ( 1 ,2 ,3 ); (4 Replies)
Discussion started by: nnani
4 Replies

7. Shell Programming and Scripting

Combine two parts of a file

Hello All, I have a file like this APPLY ( 'INSERT INTO brdcst_media_cntnt ( cntnt_id ,brdcst_media_cntnt_cd ,cntnt_prvdr_cd ,data_src_type_cd ,cntnt_titl_nm ,cntnt_desc ,batch_dt ,batch_id ) VALUES ( :cntnt_id (3 Replies)
Discussion started by: nnani
3 Replies

8. Shell Programming and Scripting

Getting various parts from the log

I am dealing with some app log, see example below: 22:16:13.601 ClientSession(905)--Connection(5)--SELECT GETDATE() 22:16:13.632 ClientSession(158)--Connection(5)--SELECT 1 22:16:13.632 ClientSession(848)--Connection(6735)--SELECT 1 So far I needed to collect certain column from it, such as... (3 Replies)
Discussion started by: migurus
3 Replies

9. Shell Programming and Scripting

How to get first four parts of the string?

I have the string: XXXX.YYYY_ZZZ.20180724.01.txt I need to get rid of .txt and get full four parts XXXX.YYYY_ZZZ.20180724.01 I did: CTL=`echo XXXX.YYYY_ZZZ.20180724.01.txt | rev | cut -d"." -f4 | rev` But got only YYYY_ZZZ What should I do to get all four parts of that... (4 Replies)
Discussion started by: digioleg54
4 Replies
bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
All times are GMT -4. The time now is 05:58 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy