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Full Discussion: How to get list of files only using ls without combining it with other command?
Top Forums Shell Programming and Scripting How to get list of files only using ls without combining it with other command? Post 302860875 by Nikhath on Monday 7th of October 2013 11:49:27 AM
Old 10-07-2013
Thanks for the correction. The first code fragment contains a typo. It is actually a combination of ls and grep.

Code:
ssh ${aSrcHOST} ls ${aSrcDIR}/|grep -vi OK$ > filelist.txt

Here , I am trying to connect to aSrcHOST and fetch the list of files names present in aSrcDIR by filtering out ok/OK files. Hence using grep -vi

This is working fine and fetching all the file names except files ending with ok/OK and dumping the list of files names in filelist.txt.

But , this command is also picking up the sub directory names inside in aSrcDIR.
This is what I want to avoid. I want only files to be picked up and not the directory names.

Please help.
 

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LEARN ABOUT ULTRIX

zgrep

ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep	options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

																	  ZGREP(1)
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