SAS Program:
I want to remove the commented part(/* Data step */) alone. I have tried using sed command but it is deleting the entire line itself. i need unix command to separate this and get the output as shown below.
Output :
Last edited by Franklin52; 07-20-2013 at 09:30 AM..
Reason: Please use code tags
Hi All,
Im trying to write a Unix FTP batch file within a program called SAS. Now i already have one for windows which works fine, but it doesnt work within unix.
I've been told that some of the commands are different from Windows to Unix, and ive looked round and am completely stumped...
... (0 Replies)
Here is the famous line 2238 of Unix V6 which is part of some of the most delicate parts of the kernel, context switching.
This comment received huge publicity and just may be the the most famous source code comment in computing history.
2230 /*
2231 * If the new process paused because it... (0 Replies)
I want to replace this line : "test compare visible] true" and make it "#test compare visible] true".
How can I do it ? And it should be checked in many sub folder files also. (6 Replies)
Hi all,
I would want to remove all comments from my ruby/rails program. It may seem like a simple task, but it is not so. Because you need to have your tool implemented as like your language parser which is actually not so easy.
And am in the search of it, to remove comment from ruby/rails.... (4 Replies)
Again a comment removal requirement from me, refer my previous problem & solution for removing comment from ruby scripts: https://www.unix.com/shell-programming-scripting/118296-best-way-removing-comment-ruby-program.html
This time, it is for stripping of comments from Shell Script. I search for... (2 Replies)
I have a requirement where I want to add a comment '#' in my crontab, run a process, than remove the '#' I added.
Example cron
#5,10 * * * * ls -lt /tmp
10,5 * * * * ls -lt /var
I would like to be able use sed or awk to add a '#' at the begining of each
line. After the command... (4 Replies)
I need to comment the lines starting with pattern "exclude" or "exclude=". If the work exclude comes at any other part, ignore it. Also, ignore, excludes, excluded etc. Ie only comment the line starting with exclude.
File contents.
exclude
exclude=
hi I am excluded
excludes
excludes=
... (9 Replies)
I have tried a lot, Need your help guys.
SAS Program:
data one ; /* Data step */
Input name $; /*Dec variables*/
I want to remove the commented part(/* Data step */) alone. I have tried using sed command but it is deleting the entire line itself. i need unix command to separate this and... (1 Reply)
i have to remove the commented (/* . . . .*/) part which starts in one line and ends in other.help me with generic code because i have 1000 to 10k lines code which i have to remove.
data one;
set work.temp;
input name age;
infile filename;
/* dfsdf
dsfs
sdfdf
dsdd
sdfsf
sdfsf
sfs... (4 Replies)
Hi All,
I am copying a file from windows to UNIX. After that copying it have the ctrl+M character in the file at the line break. But the file contains the data that also have ctrl+M. I want to re move the ctrl+M at the end of the line alone.
My file structure is XML and last line doesnt... (3 Replies)
Discussion started by: Agantrope
3 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)