QUESTION: How can I cut out the date from just the first line and reformat it to 31-Jul-2007? I'll restate the question at the bottom again...
DESCRIPTION: I need to cut a date out of a file - an example of the date's format in the file is 2007-07-31. It's in the 5th field and is separated... (1 Reply)
Hi All,
How can i use the cut option to only output the number of rows, which is 2 is this case ? Pls note that the number of digit before the delimiter ":" is always varying.
$ grep -n uuu xxx
2:** xxx yyy gg 44 tt uuu 2007
$ (2 Replies)
Hi,
I've a situation where,
a=xxx.yyy.zzz.txt
EXTN=`echo $a | cut -d . -f2`
Using the above code it delimites and will return "yyy.zzz.txt" to EXTN. But i need to get only the extension "txt". so as per the above code it delimits in the first "." itself. Can anyone help how to do... (6 Replies)
Is there a way to use a word as a delimiter with cut? Or is there a way to use sed or awk with a word as a delimiter? I don't care which program I use for a delimiter I just want to use a word as a delimiter. (2 Replies)
I need to cut or otherwise get the 4th and 5th position output of
for i in `date +%H` ; do vnstat --dumpdb | grep "h;$i" ; done
example output is:
h;13;1310318701;443;93
I only need ";443;93" from any given run of "for i in `date +%H` ; do vnstat --dumpdb | grep "h;$i" ; done"
Thanks... (3 Replies)
HI,
I have a file like below
"103865","103835","Zming","","Zhu","103965","Sunnyvale","US",
"116228","116227","Morlla","","Kowalski","113228","Paese "(Treviso)""IT"
I want to validate the 7th column which is below.
"Sunnyvale"
"Paese
In the above 7th column Paese is not ended with... (9 Replies)
hi all,
suppose a string:
abc/def/ghi/jkl/mn.txt
and i want to get the file name without the path.
however, different files have different paths, therefore the number of delimiter is uncertain.
thanks so much! (3 Replies)
Hi all,
I have a number of strings like below:
//mnt/autocor/43°13'(33")W/
and i'm trying to get the numbers in this string, for example
431333
please help
thanks ahead (14 Replies)
i have list of names in a text file and I wanted to delete the commas en every line.
for example: inside the text is a list of names in it with commas after each line. I wanted to delete these commas. which command must I execute for this?
unix,
dale,
shawn,
aaron, (4 Replies)
Discussion started by: garfish
4 Replies
LEARN ABOUT ULTRIX
cat
cat(1) General Commands Manual cat(1)Name
cat - concatenate and print data
Syntax
cat [ -b ] [ -e ] [ -n ] [ -s ] [ -t ] [ -u ] [ -v ] file...
Description
The command reads each file in sequence and displays it on the standard output. Therefore, to display the file on the standard output you
type:
cat file
To concatenate two files and place the result on the third you type:
cat file1 file2 > file3
To concatenate two files and append them to a third you type:
cat file1 file2 >> file3
If no input file is given, or if a minus sign (-) is encountered as an argument, reads from the standard input file. Output is buffered in
1024-byte blocks unless the standard output is a terminal, in which case it is line buffered. The utility supports the processing of 8-bit
characters.
Options-b Ignores blank lines and precedes each output line with its line number.
-e Displays a dollar sign ($) at the end of each output line.
-n Precedes all output lines (including blank lines) with line numbers.
-s Squeezes adjacent blank lines from output and single spaces output.
-t Displays non-printing characters (including tabs) in output. In addition to those representations used with the -v option, all tab
characters are displayed as ^I.
-u Unbuffers output.
-v Displays non-printing characters (excluding tabs and newline) as the ^x. If the character is in the range octal 0177 to octal 0241,
it is displayed as M-x. The delete character (octal 0177) displays as ^?. For example, is displayed as ^X.
See Alsocp(1), ex(1), more(1), pr(1), tail(1)cat(1)