Hello!
Why does my SuSE GNU/Linux machine swap?
I have a Gig of ram, currently 14MBs of free RAM, 724MB - buffers and caches...
That is 685MB of cached RAM, then kernel really should'nt have to swap, It should release cached memory in my thinkin...
It has only swaped 3MB's but still,... (3 Replies)
Hi,
I am attempting to replace several similar words with another word in vi. Here is what I have written for the script:
3dTcat -prefix SuperBrik_4WAY_HRF ../JULY10_2007A/results2TENT/stats.JULY10_2007A+tlrc ../JULY10_2007G/results2TENT/stats.JULY10_2007G+tlrc... (1 Reply)
Hi
I have afile with 15fields,say f1,f2....f15 delimited on comma. How can i swap the f1,f15 fields using unix shell commands or any script?
Thanks (3 Replies)
Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!
1. The problem statement, all variables and given/known data:
The assignment is to convert a text table to csv format. I've got the cleaning up done, but I need to swap two... (0 Replies)
I have some text:
<date>some_date</date>
<text>some_text</text>
<name>some_name<name>
and I want to transform it to smthng like that:
some_name on some_date: some_text
I've tried sed:
sed 's/<text>\(.*\)<\/text>
<name>\(.*\)<\/name>/\2 - \1/'
but it says unterminated... (13 Replies)
Hi All,
Sorry if this question has been posted elsewhere, but I'm hoping someone can help me! Bit of an AWK newbie here, but I'm learning (slowly!)
I'm trying to cobble a script together that will save me time (is there any other kind?), to swap two fields (one containing whitespace), with... (5 Replies)
Hi Friends ,
I have file1.txt
1|b|46|123|47673|348738
2|c|63|124|7346|4783
3|y|45|125|5555|78789
output should swap the 4th field to the first field.
output
123|1|b|46|47673|348738
124|2|c|63|7346|4783
125|3|y|45|5555|78789 (3 Replies)
Hallo Team,
I would like to replace filed 4 and 7 with filed 39 how can i achieve this ?
-bash-3.2$ cat dip1.csv| cut -f4,7,24,36,39 -d","|sort -u
+27113996891,+27113996891,196.35.130.52,828854047,+27873500077
+27116452690,+27825702918,10.0.109.13:5060,+27116452690,+27116452690... (2 Replies)
Hi Guys
I am using SPARC-T4 (chipid 0, clock 2998 MHz), SunOS 5.10 Generic_150400-38 sun4v.
How do I see if the server was doing some swapping like yesterday?
I had a java application error with java.lang.OutOfMemoryError, now I want to check if the server was not doing some swapping at... (4 Replies)
Discussion started by: Phuti
4 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)