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Top Forums Shell Programming and Scripting How to selectively NOT output some fileds? Post 302817701 by pamu on Thursday 6th of June 2013 10:28:16 AM
Old 06-06-2013
Quote:
Originally Posted by Subbeh
That will only make the fields empty, not remove them.
Yes. That will make fields to null value.
But the ultimate aim of not including them into the output is resolved. Smilie
 

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SHTOOL-TABLE.TMP(1)					      GNU Portable Shell Tool					       SHTOOL-TABLE.TMP(1)

NAME
shtool-table - GNU shtool pretty-print a field-separated list SYNOPSIS
shtool table [-F|--field-sep sep] [-w|--width width] [-c|--columns cols] [-s|--strip strip] strsepstr... DESCRIPTION
This pretty-prints a list of strings as a table. OPTIONS
The following command line options are available. -F, --field-sep sep Separate columns using sep. Default is ":". -w, --width width Width of each column. Default is 15 characters. -c, --columns cols Number of columns. Default is 3. -s, --strip strip Strip off any characters past strip. Default is 79. EXAMPLE
# shell script shtool table -F , -w 5 -c 4 "1,2,3,4,5,6,7,8,9,10,11,12" HISTORY
The GNU shtool table command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 1999 for GNU shtool. SEE ALSO
shtool(1), tr(1), fmt(1), sh(1), awk(1), sed(1). 18-Jul-2008 shtool 2.0.8 SHTOOL-TABLE.TMP(1)
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