hi ,
This function actually gives me the last month but as a numeric value what should i do to get it as suppose :Jul
date '+%b %Y' |
{
read MONTH YEAR
MONTH=`expr "$MONTH" - 1`
echo $MONTH
}
Thanks.
Rooh (2 Replies)
Hi
I am having date as a string in DDMMYYYY format(07082008) in a variable say cdate. I want to Convert it into DD Month YYYY format(7 August 2008). Could someone help. Thanks in Advance. (2 Replies)
Hi,
If I am having month like 2/3/4 then how can I convert it into month name like Feb/Mar/Apr....
Is there any defined function in Perl ?? (2 Replies)
Hello,
How do I convert unix timestamp value to 'normal' date format - to get year month and day values ?
Looks like it's easy to do using GNU date (linux systems). But how do I do tthis on AIX ?
I don't want to write C program, any ways to do that using unix shells ?
thanks (1 Reply)
I have a value in a file i am processing that has a date like "2012-Jun-13"
how can I convert a date like that 2012-06-13?
Am I stuck building an array of three digit months and corresponding numbers and running through the logic of figuring out the number??
or can I convert this with... (1 Reply)
How to convert date format such as 7/18/2015 to the number of month from requesting date 'date' in sh scripting ?
Let say I have output in my log.txt -> 7/18/2015. How I convert it to the full number of month starting from 'date' till 7/18/2015 in shell scripting ? Thanks in advance. (1 Reply)
Hi,
I have a script that accepts an input date from the user in yyyy-mm-dd format.
I need to get the mm-dd part and convert it to month name.
example:
2011-11-15
I want that to become "Nov 15"
I don't have the GNU date, I am using an AIX os.
Thanks. (1 Reply)
# Sample input
common-name www.test.com.au
expiration Dec 21 01:00:31 2017 GMT
common-name www.test1.com.au
expiration Jan 19 04:41:03 2018 GMT
# Desired Output
# Field 1: Domain name
# Field 2: Date/time converted to Austraian format DD/MM/YYYY and on the same line as Domain Name.
#... (7 Replies)
Hi Folks -
Linux Version = Linux 2.6.39-400.128.17.el5uek x86_64
I have a process that determines the start and end load periods for an Oracle data load process.
The variables used are as follows follows:
They are populated like such:
However, the load requires the month to be the... (11 Replies)
Discussion started by: SIMMS7400
11 Replies
LEARN ABOUT MOJAVE
string::rewriteprefix
String::RewritePrefix(3) User Contributed Perl Documentation String::RewritePrefix(3)NAME
String::RewritePrefix - rewrite strings based on a set of known prefixes
VERSION
version 0.007
SYNOPSIS
use String::RewritePrefix;
my @to_load = String::RewritePrefix->rewrite(
{ '' => 'MyApp::', '+' => '' },
qw(Plugin Mixin Addon +Corporate::Thinger),
);
# now you have:
qw(MyApp::Plugin MyApp::Mixin MyApp::Addon Corporate::Thinger)
You can also import a rewrite routine:
use String::RewritePrefix rewrite => {
-as => 'rewrite_dt_prefix',
prefixes => { '' => 'MyApp::', '+' => '' },
};
my @to_load = rewrite_dt_prefix( qw(Plugin Mixin Addon +Corporate::Thinger));
# now you have:
qw(MyApp::Plugin MyApp::Mixin MyApp::Addon Corporate::Thinger)
METHODS
rewrite
String::RewritePrefix->rewrite(\%prefix, @strings);
This rewrites all the given strings using the rules in %prefix. Its keys are known prefixes for which its values will be substituted.
This is performed in longest-first order, and only one prefix will be rewritten.
If the prefix value is a coderef, it will be executed with the remaining string as its only argument. The return value will be used as the
prefix.
AUTHOR
Ricardo Signes <rjbs@cpan.org>
COPYRIGHT AND LICENSE
This software is copyright (c) 2013 by Ricardo Signes.
This is free software; you can redistribute it and/or modify it under the same terms as the Perl 5 programming language system itself.
perl v5.18.2 2013-10-15 String::RewritePrefix(3)