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1. Shell Programming and Scripting
# Sample input
expiration Dec 21 01:00:31 2017 GMT
expiration Jan 19 04:41:03 2018 GMT
# Desired Output
# Field 1: Domain name
# Field 2: Date/time converted to Austraian format DD/MM/YYYY and on the same line as Domain Name.
#... (7 Replies)
Discussion started by: thangbom
2. Shell Programming and Scripting
i`m looking for some way to add to some date an partial number of months, for example to 2015y 02m 27d + 2,54m
i need to write this script in php or bash or sh or mysql or perl in normal time o unix time
i`m asking or there are any simple way to add partial number of month to some... (14 Replies)
Discussion started by: bacarrdy
3. Shell Programming and Scripting
I have a script that accepts an input date from the user in yyyy-mm-dd format.
I need to get the mm-dd part and convert it to month name.
I want that to become "Nov 15"
I don't have the GNU date, I am using an AIX os.
Thanks. (1 Reply)
Discussion started by: erin00
4. UNIX for Advanced & Expert Users
From the below code i can see the value in M=05 and +1 added i.e 6.
i am calling those 2 variables and the output is giving as 01-6-2013. But the required output should be 01-Jun-2013. Please let me know how can i get this format.
if ; then
... (4 Replies)
Discussion started by: kiranparsha
5. Shell Programming and Scripting
How to convert date format such as 7/18/2015 to the number of month from requesting date 'date' in sh scripting ?
Let say I have output in my log.txt -> 7/18/2015. How I convert it to the full number of month starting from 'date' till 7/18/2015 in shell scripting ? Thanks in advance. (1 Reply)
Discussion started by: amerabest
6. Shell Programming and Scripting
I am trying to come up with a shell script to count a specific word in a logfile on each day of this month, last month and the month before. I need to produce this report and email it to customer.
Any ideas would be appreciated! (5 Replies)
Discussion started by: pnara2
7. UNIX for Dummies Questions & Answers
month=`date +%m`gives current month
Howto print previous month (current month minus 1) with Solaris date and ksh (7 Replies)
Discussion started by: slashdotweenie
How do I convert unix timestamp value to 'normal' date format - to get year month and day values ?
Looks like it's easy to do using GNU date (linux systems). But how do I do tthis on AIX ?
I don't want to write C program, any ways to do that using unix shells ?
thanks (1 Reply)
Discussion started by: vilius
9. Shell Programming and Scripting
I am having date as a string in DDMMYYYY format(07082008) in a variable say cdate. I want to Convert it into DD Month YYYY format(7 August 2008). Could someone help. Thanks in Advance. (2 Replies)
Discussion started by: rspk_praveen
10. UNIX for Dummies Questions & Answers
This function actually gives me the last month but as a numeric value what should i do to get it as suppose :Jul
date '+%b %Y' |
read MONTH YEAR
MONTH=`expr "$MONTH" - 1`
Rooh (2 Replies)
Discussion started by: rooh