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Top Forums Shell Programming and Scripting Trouble with variable assignment and reading in shell scripting Post 302808297 by Yoda on Thursday 16th of May 2013 11:32:00 AM
Old 05-16-2013
Using array is the best option for this requirement.

You could code something like below:
Code:
#!/bin/bash

typeset -a table_name
typeset -i c

while read tn
do
        (( ++c ))
        table_name[c]="${tn}"
done < inputfile

Now you have each table names stored in the indexed array.

For further reference refer: Bash Array (link removed)
This User Gave Thanks to Yoda For This Post:
 

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PG_COPY_FROM(3) 														   PG_COPY_FROM(3)

pg_copy_from - Insert records into a table from an array

SYNOPSIS
bool pg_copy_from (resource $connection, string $table_name, array $rows, [string $delimiter], [string $null_as]) DESCRIPTION
pg_copy_from(3) inserts records into a table from $rows. It issues a COPY FROM SQL command internally to insert records. PARAMETERS
o $connection - PostgreSQL database connection resource. o $table_name - Name of the table into which to copy the $rows. o $rows - An array of data to be copied into $table_name. Each value in $rows becomes a row in $table_name. Each value in $rows should be a delimited string of the values to insert into each field. Values should be linefeed terminated. o $delimiter - The token that separates values for each field in each element of $rows. Default is TAB. o $null_as - How SQL NULL values are represented in the $rows. Default is N ("\N"). RETURN VALUES
Returns TRUE on success or FALSE on failure. EXAMPLES
Example #1 pg_copy_from(3) example <?php $db = pg_connect("dbname=publisher") or die("Could not connect"); $rows = pg_copy_to($db, $table_name); pg_query($db, "DELETE FROM $table_name"); pg_copy_from($db, $table_name, $rows); ?> SEE ALSO
pg_copy_to(3). PHP Documentation Group PG_COPY_FROM(3)
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