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Shell Programming and Scripting
Grep a part of file based on string identifiers
Post 302783353 by vivek d r on Wednesday 20th of March 2013 10:19:13 AM
03-20-2013
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hey gurus,
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HI,
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i have something like this in a file called mysqldump.sql
--
-- Table structure for table `Table11`
--
DROP TABLE IF EXISTS `Table11`;
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consider the following is the contents of the file
cat 11.sql
drop procedure if exists hoop1 ;
Delimiter $$
CREATE PROCEDURE hoop1(id int)
BEGIN
END
$$
Delimiter ;
.
.
.
.
drop procedure if exists hoop2;
Delimiter $$
CREATE PROCEDURE hoop2(id int)
BEGIN
END
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I was wondering if it was possible to grep a pattern based on the surround text. For example, if i have an input file like this:
titleA
titleB
titlex
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cat fileanme.txt
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custom2=,
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here below is a part of the file
cat fileName.txt
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FIXED=false
DATE= 2013-02-19 03:46:04.4
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I have a file containing texts and indexes. I need the text between (and including ) INDEX and number "1" alone in line. I have managed this:
awk '/INDEX/,/1$/{if (!/1$/)print}' file1.txt
It works for all indexes.
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Hi All,
I am trying to fetch the particular content from the result of grep command.
I am using
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above statement giving me
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I have the file:
s3_T0(2) Pos "1" "2"
s1_T1(2) Pos "1" "2"
---
0 0
1 0
0 1
1 1
---
1 2 "tau0"
1 2 "h10"
I want to patternmatch on ---
and get only the third part i.e.
1 2 "tau0"
1 2 "h10"
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LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1) NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)