Sponsored Content
Top Forums Shell Programming and Scripting Pass Parameters to awk command Post 302752355 by Yoda on Monday 7th of January 2013 12:39:45 AM
Old 01-07-2013
Code:
FILE="partial.txt"
LEN=285

echo | awk -v l="$LEN" -v file="$FILE" '{s="%-"l"s\n"; while(( getline line < file  ) > 0 ) { print s,line; } } '

This User Gave Thanks to Yoda For This Post:
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

How to pass parameters to an awk file?

I have an awk file where I need to pass a filename and a value as a parameter from a sh script. I need to know how to pass those values in the sh script and how to use the same in the awk file. Thanks in advance!!! Geetha (3 Replies)
Discussion started by: iamgeethuj
3 Replies

2. Shell Programming and Scripting

Pass command line arguments to awk

I am trying to pass max as a sommand line argument when I call awk. Made the modification in the BEGIN but it is not working I'm getting an error as below: awk: txsrx.awk:82: (FILENAME=jcd.tx FNR=4161) fatal: cannot open file `40' for reading (No such file or directory) Somehow it... (2 Replies)
Discussion started by: kristinu
2 Replies

3. Shell Programming and Scripting

Pass parameters to function

Hi, for example I have this function: function get_param () { test=echo "some string" test2=echo "someother string" } I want to call this function and get test or test2 result, how do I do that ? Thank you (2 Replies)
Discussion started by: ktm
2 Replies

4. Shell Programming and Scripting

want to pass parameters to awk script from shell script

Hello, I have this awk script that I want to execute by passing parameters through a shell script. I'm a little confused. This awk script removes duplicates from an input file. Ok, so I have a .sh file called rem_dups.sh #!/usr/bin/sh... (4 Replies)
Discussion started by: script_op2a
4 Replies

5. Shell Programming and Scripting

need to pass parameters to working and tested awk script

I have a working and tested AWK script that removes duplicates from an input file and generates an output file without the duplicates. I had help from my other post to develop it: ... (3 Replies)
Discussion started by: script_op2a
3 Replies

6. Shell Programming and Scripting

pass shell parameters to awk does not work

Why does this work for myfile in `find . -name "R*VER" -mtime +1` do SHELLVAR=`grep ^err $myfile || echo "No error"` ECHO $SHELLVAR done and outputs No error err ->BIST Login Fail 3922 err No error err ->IR Remote Key 1 3310 err But... (2 Replies)
Discussion started by: alan
2 Replies

7. Emergency UNIX and Linux Support

Pass two parameters

Hi I have a batch file aaa.exe which needs two input parameters: Usually the command's format likes aaa 555 10000 But I want to use parameters to do it. aaa $1 $2 These two parameters come from a text file list.txt 41800497 41801375 41814783 41816135 41814930 41816135 41819987 41820843... (4 Replies)
Discussion started by: zhshqzyc
4 Replies

8. Shell Programming and Scripting

Bash- Command run from script does not pass full parameters with spaces inside

There's a JavaScript file that I call from command line (there's a framework) like so: ./RunDiag.js param1:'string one here' param2:'string two here' I have a shell script where I invoke the above command. I can run it in a script as simple as this #!/bin/bash stuff="./RunDiag.js... (4 Replies)
Discussion started by: AcerAspirant
4 Replies

9. Shell Programming and Scripting

Cannot pass rsh and awk command into a variable

Hello, I'm having some issues getting a home dir from a remote server passed to a variable. Here is what I have so far: rsh server "(ls -ld /home*/user | awk '{print \$9}')" /home3/userThat works fine and brings back what I need. But when I try to add it to a variable it goes all... (3 Replies)
Discussion started by: elcounto
3 Replies

10. Shell Programming and Scripting

Pass awk field to a command line executed within awk

Hi, I am trying to pass awk field to a command line executed within awk (need to convert a timestamp into formatted date). All my attempts failed this far. Here's an example. It works fine with timestamp hard-codded into the command echo "1381653229 something" |awk 'BEGIN{cmd="date -d... (4 Replies)
Discussion started by: tuxer
4 Replies
bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
All times are GMT -4. The time now is 03:32 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy