I am very thankful to you Don Cragun for helping me in writing scripts and explaining them as well.
I am very new in this field of shell scripting but I cannot rely on other programming language because I am not expert in any language. I have started reading shell scripting books, but its difficult for me to figure out what to write in a script. I don't know sometimes what are the functions or commands available in shell scripting I can use. But, when you write script then I come to know about lot of things and I try to read it.
I know I should write my own script and post here for help, but sometimes even I am unable to guess how I have to start. I have found this forum as my best guide on the internet.
I am adding more information and real values for the last post.
atom.txt has less than 1000 entries, so Ids don't have more than 3 digits.
There are 30 values in Group 10 with comma separator, Group 72 has 26 values and so on, Id_of_Branches means number of values in each group.
There are not 33 fields on every line (one for Group ID, one for Centre ID, one for Branches ID, and one for each of 30 branches). There are not 3 + value_of_3rd_field fields?
I have two files and I combined them into one g.txt (using comma separator for Id_of branches), two files are:
Code:
First file:
Group: 0 Number of Branches: 1
0 001
Centre: 001 Branches: 1
Group: 1 Number of Branches: 1
0 002
Centre: 002 Branches: 1
Group: 2 Number of Branches: 1
0 003
Centre: 003 Branches: 1
Group: 3 Number of Branches: 6
0 009
1 004
2 008
3 007
4 005
5 006
Centre: 006 Branches: 6
Group: 4 Number of Branches: 2
0 010
1 011
Centre: 010 Branches: 2
Group: 5 Number of Branches: 2
0 012
1 013
Centre: 012 Branches: 2
Upto more than 600 groups
Second file:
Group No:
10 Centre: 052 Branches: 31
73 Centre: 184 Branches: 25
397 Centre: 607 Branches: 23
398 Centre: 640 Branches: 22
86 Centre: 245 Branches: 19
71 Centre: 167 Branches: 12
78 Centre: 220 Branches: 11
18 Centre: 084 Branches: 10
09 Centre: 022 Branches: 10
400 Centre: 650 Branches: 9
I wish to have 10 files for 10 groups (as per second file) each with pattern corresponding to the Id _of_Branches (from first file) in each group.
Centre.txt (only one file) is supposed to contain patterns corresponding to Centre Id from each group.
Hello,
I have a file.txt with 20000 lines and 2 columns each which consists of current_filename and new_filename . I want to create a script to find files in a directory with current_filename and move it to new folder with new_filename.
Could you please help me how to do that??
... (2 Replies)
Hi,
I have a file which is:-
1 6 4 8 2 3
2 1 9 3 2 1
3 3 5 6 3 1
4 9 7 8 2 3
I would like to sort from field $2 to field $6 for each of the line to:-
1 2 3 4 6 8
2 1 1 2 3 9
3 1 3 3 5 6
4 2 3 7 8 9
I came across this Arrays on example 26-6. But it is much complicated. I am... (7 Replies)
Hi,
I'm trying to read a file containing lines with spaces in them.
The inputfile looks like this
------------------------------
Command1 arg1 arg2
Command2 arg5 arg6 arg7
-------------------------------
The shell code looks like this...
lines=`awk '{ print }' inputfile`
... (2 Replies)
I'm trying to reformat some tide information into a useable format and failing.
Input file is....
4452 CHENNAI (MADRAS)
13°06'N, 80°18'E India East Coast 01 June 2009 UT(GMT)
Data Area 3. Indian Ocean (northern part) and Red Sea to Singapore
01/06/2009
00:00 0.7 m
00:20 0.7 m
00:40... (3 Replies)
Hi Everyone,
I have an input file in the following format:
score.file1.txt
contig00045 length=566 numreads=19 1047 0.0
contig00055 length=524 numreads=7 793 0.0
contig00052 length=535 numreads=10 607 e-176
contig00072 length=472 numreads=46 571 e-165... (8 Replies)
I would like to write a script to extend this command to a general case:
BEGIN {s_0=0;n_0=0}{n_0++;s_0+=($51-$1)^2}END {print sqrt(s_0/n_0)}
i.e. so that
BEGIN {s_0=0;n_0=0}{n_0++;s_0+=($51-$1)^2}END {print sqrt(s_0/n_0)}
BEGIN {s_1=0;n_1=0}{n_1++;s_1+=($51-$2)^2}END {print... (3 Replies)
Hi, I am also a newbie in awk and trying to find solution of my problem.
I have one reference file 1.txt with 2 columns and I want to search other 10 files (a.txt, b.txt......h.txt each with 5 columns) corresponding to the values of 2nd column from 1.txt. If the value from 2nd column from 1.txt... (0 Replies)
Hi, I am also a newbie in awk and trying to find solution of my problem.
I have one reference file 1.txt with 2 columns and I want to search other 10 files (a.txt, b.txt......h.txt each with 5 columns) corresponding to the values of 2nd column from 1.txt. If the value from 2nd column from 1.txt... (33 Replies)
Hi
I am a newbie starting bash and I have a simple need to return the result of an operation from awk to bash. basically I want to use awk to tell me if "#" exists in a string, and then back in bash, i want to do an IF statement on this return in order to do other things. In my bash shell I... (2 Replies)
Hi!
I have a new problem with awk, this time I think is because I'm using it in bash and I don't know how to put the valor of the variable in awk. Here is the code:
#!/bin/bash
for i in 1 2 3 4 5
do
a=$i
b=$
awk '$1>=a&&$1<=b {print $1,$2,$3}'>asdf test... (3 Replies)
Discussion started by: florpi
3 Replies
LEARN ABOUT PHP
cubrid_fetch
CUBRID_FETCH(3) 1 CUBRID_FETCH(3)cubrid_fetch - Fetch the next row from a result setSYNOPSIS
mixed cubrid_fetch (resource $result, [int $type = CUBRID_BOTH])
DESCRIPTION
The cubrid_fetch(3) function is used to get a single row from the query result. The cursor automatically moves to the next row after get-
ting the result.
PARAMETERS
o $result
-$result comes from a call to cubrid_execute(3)
o $type
-Array type of the fetched result CUBRID_NUM, CUBRID_ASSOC, CUBRID_BOTH, CUBRID_OBJECT. If you want to operate the lob object, you
can use CUBRID_LOB.
RETURN VALUES
Result array or object, when process is successful.
FALSE, when there are no more rows; NULL, when process is unsuccessful.
The result can be received either as an array or as an object, and you can decide which data type to use by setting the $type argument. The
$type variable can be set to one of the following values:
oCUBRID_NUM : Numerical array (0-based)
oCUBRID_ASSOC : Associative array
oCUBRID_BOTH : Numerical & Associative array (default)
oCUBRID_OBJECT : object that has the attribute name as the column name of query result
When $type argument is omitted, the result will be received using CUBRID_BOTH option as default. When you want to receive query result in
object data type, the column name of the result must obey the naming rules for identifiers in PHP. For example, column name such as
"count(*)" cannot be received in object type.
EXAMPLES
Example #1
cubrid_fetch(3) example
<?php
$conn = cubrid_connect("localhost", 33000, "demodb");
$req = cubrid_execute($conn, "SELECT * FROM stadium WHERE nation_code='GRE' AND seats > 10000");
printf("%-40s %-10s %-6s %-20s
", "name", "area", "seats", "address");
while ($row = cubrid_fetch($req)) {
printf("%-40s %-10s %-6s %-20s
",
$row["name"], $row["area"], $row["seats"], $row["address"]);
}
// if you want to operate lob object, you can use cubrid_fetch($req, CUBRID_LOB)
cubrid_close_request($req);
cubrid_disconnect($conn);
?>
The above example will output:
name area seats address
Panathinaiko Stadium 86300.00 50000 Athens, Greece
Olympic Stadium 54700.00 13000 Athens, Greece
Olympic Indoor Hall 34100.00 18800 Athens, Greece
Olympic Hall 52400.00 21000 Athens, Greece
Olympic Aquatic Centre 42500.00 11500 Athens, Greece
Markopoulo Olympic Equestrian Centre 64000.00 15000 Markopoulo, Athens, Greece
Faliro Coastal Zone Olympic Complex 34650.00 12171 Faliro, Athens, Greece
Athens Olympic Stadium 120400.00 71030 Maroussi, Athens, Greece
Ano Liossia 34000.00 12000 Ano Liosia, Athens, Greece
SEE ALSO cubrid_execute(3), cubrid_fetch_array(3), cubrid_fetch_row(3), cubrid_fetch_assoc(3), cubrid_fetch_object(3).
PHP Documentation Group CUBRID_FETCH(3)
01-04-2013
