Sponsored Content
Top Forums Shell Programming and Scripting Printf transforms \x0a into \x00 Post 302750167 by Don Cragun on Monday 31st of December 2012 04:32:33 AM
Old 12-31-2012
Quote:
Originally Posted by vomv1988
If

Code:
printf '\x0a' | xxd -cols 1

produces

Code:
0000000: 0a  .

then, why does

Code:
printf '%c' "`printf '\x0a'`" | xxd -cols 1

produce

Code:
0000000: 00  .

??
Because command substitution (`command` or $(command)) removes trailing newlines from the output of the commands performed.
These 2 Users Gave Thanks to Don Cragun For This Post:
 

6 More Discussions You Might Find Interesting

1. Programming

printf

What is the output of the following program considering an x86 based parameter passing sequence where stack grows towards lower memory addresses and that arguments are evaluated from right to left: int i=10; int f1() { static int i = 15; printf("f1:%d ", i); return i--; } main() {... (2 Replies)
Discussion started by: arunviswanath
2 Replies

2. Shell Programming and Scripting

[AWK] read lines with \x00 symbol

I want to read a large (~1-4Gb) txt file with fields separated by "," and line separator "\n". Unfortunately, file contains \x00 (zero ASCII) symbols AWK treats them as end of line + it ignores reminder of the line after the \x00. As a simple example: echo "\0060\0061\000\0060\0063" | nawk... (6 Replies)
Discussion started by: Murfury
6 Replies

3. Shell Programming and Scripting

remove \x0a in unix

hi all, i have a flat file delimited by pipe (|), and i'm loading it to sybase, the problem is when i do a select to the table of the database, the last field has new line ascii (\x0a): 38,'0\x0a ' 88,'076004074028\x0a ' 27,'076004075023\x0a ' how can i remove the \x0a from... (1 Reply)
Discussion started by: DebianJ
1 Replies

4. Shell Programming and Scripting

Replacing hex characters '\x0D' with '\x0D\x0A'

Hello All, I have a requirement where I need to replaced the hex character - '\x0D' with 2 hex characters - 'x0D' & 'x0A' I am trying to use SED - But somehow its not working. Any pointers? Also the hex character '\x0D' can occur anywhere in the line. Can this also be accomplished... (6 Replies)
Discussion started by: paragkalra
6 Replies

5. Virtualization and Cloud Computing

Install Xen vm on centos5.5 crashed "x00\x00\x00\x00\"

Hi, everyone: I'm new to xen. When I install a vm on centos5.5, I got xen crashed: # virt-install -n centos5 -r 512 --vcpus=1 --disk path=/home/mycoy/centos5.img,size=8 --nographics -l http://mirror01.idc.hinet.net/CentOS/5.5/isos/i386/CentOS-5.5-i386-netinstall.iso when... (1 Reply)
Discussion started by: mycoy
1 Replies

6. Shell Programming and Scripting

[Perl] Does m/\x0A/ same as m/\x{0A}/ ?

Perl allow hex character with just one digit. Such as \x0 \x9 \xA. How to force to use 2 digits in m// and s///. Such as \x00 \x09 \x0A. ---------- Post updated at 05:20 PM ---------- Previous update was at 03:38 PM ---------- I don't know why these code replace as text, not a real hex... (0 Replies)
Discussion started by: natong
0 Replies
bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
All times are GMT -4. The time now is 01:54 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy