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Top Forums Shell Programming and Scripting How to store result of grep into a variable? Post 302727515 by twistedpair on Tuesday 6th of November 2012 10:54:59 AM
Old 11-06-2012
Question How to store result of grep into a variable?

In a directory i have a file *output* whose contents are changing for every simulation.
Code:
zgrep "trace file is" *output* | zgrep g

o/p: trace file is Int_01.1352176388z4f56ec33.0.trace.gz

I want to extract "Int_01.1352176388z4f56ec33.0.trace.gz" from the above result into a variable.

i tried this, but getting errors
Code:
$temp='zgrep "trace file is" *output* | zgrep gz';
$final = substr("$temp",15);

plz help

Last edited by Scrutinizer; 11-06-2012 at 12:16 PM.. Reason: code tags
 

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ZGREP(1)                                                      General Commands Manual                                                     ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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