I have the results of a grep with -n store in a shell variable
ie
VAR=`grep -n -e 'PATTERN' file`
How ever I am missing the line breaks in the variable , How do I store the resualts of grep with many lines in to a variables. I want the varable should be the sawmway as we do the grep
grep... (3 Replies)
:)
Suppose,I have one table A. Table A have one column. Table A have 10 rows. I want this 10 rows store into shell script variable.
like
#!/bin/ksh
v_shell_var=Hi
here in call oracle , through loop How can I store table A's 10 rows into v_shell_var (Shell Script Array).
Regards,
Div (4 Replies)
I have a variable A
echo $A
5060
I am exporting the value X,Y,Z and it id fetching right thing and When I run
C=`${X} -l ${Y} ${Z} "trap '' INT;. ~/.profile >/dev/null 2>/dev/null; netstat -na | grep \$A`"
here it is going to same directory and also running netstat -na | grep 5060
... (4 Replies)
Hello,
I have a question regarding the awk command. Here is the line I need to grep:
1 F= -.13250138E+03 E0= -.13249556E+03 d E =-.174650E-01 mag= 35.2157
Instead of displaying the number in red I would like to store it as a variable such as X. Is there a way to do this? Thanks for any... (3 Replies)
Hi,
I have a file contains attribute value pair like..
..name=erick rollno=583.0 pass=recon..
From the above line, i need to grep for only "rollno" and store "rollno=583.0" in a variable.
Pls suggest (6 Replies)
I am facing a problem while storring the grep results into a variable. I need to count the occurence of the pattern \, in a file and store that in a variable. I have given the below command
p=`grep -c '\\,' filename`
But while echoing the variable, i am getting the total number of lines in... (2 Replies)
Hi,
I'm trying to search a text file for a string: "energy(sigma->0)=". To do so, I executed the grep command, which returned many matches, for example:
energy without entropy = -112.16486170 energy(sigma->0) = -112.16520778
energy without entropy = -112.16488936 ... (5 Replies)
Hi ,
I was trying to store the value of a grep command to store in a variable so i can use it somewhere else in my script but i am getting error, i am using bash shell in linux:
var= `grep -n "$DATE" testfile.log | head -n 1 | sed -n 's/^\(*\).*/\1/p`
echo "$var"I get the error: unexpected... (5 Replies)
I can not figure out how to capture the $filename variable store by the bash.
#!/bin/bash
# oldest folder stored as variable for analysis, version log created, and quality indicators matched to run
dir=/home/cmccabe/Desktop/NGS/test
find "$dir" -maxdepth 1 -mindepth 1 -type d -printf... (5 Replies)
Discussion started by: cmccabe
5 Replies
LEARN ABOUT LINUX
zegrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)