10-04-2012
Change expr $i+2 to expr $i + 2.
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Hi all,
I am new to perl.
I need help adding bunch of numbers.
I have a file look like this:
1
1
2
1
2
3
1
2
3
4
1 (2 Replies)
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I add up the number of args that are not blank. It works, but the printout is a string that just keep concatenating on +1. So Ex. it goes through input of: bob toto " " tom ...I get 0+1+1+1, when all I want is 3. Any help is appreciated.
count=0
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I have to create un counter and I am unable to do an additition:
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while ]
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4. Shell Programming and Scripting
Hi all,
I am getting following output by using commands like sort, uniq and awk to the standard output.
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5. Shell Programming and Scripting
Hi all,
I am very new to shell programming and trying to learn out the basics.
I tried this:
$ echo `expr 20 + 30`
and it worked. But when i tried this,it does not work.
$ a=20
$ b=30
$ echo `expr a + b`
The error is:
expr: non-numeric argument
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Hi,
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UID: ABCD
UNAME: XYZ
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Tmiestamp: 20101208
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ModifyTImestamp:20101209
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Hi I need to do the following substitution
I have to look for line starting with ABC and add 4 ":" before the first occurence of "+"in that line
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ABC:12:Lambert:C278472:1357:0:0:0:0:2:N::::N:9045123:NAP::+DEF
output
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i need shell script to add to numbers
#!/usr/bin/sh
a=1310601600 ------> epcho time of Thu, 14 Jul 2011 00:00:00 UTC
b=864000 -------> 10 days in sec
c=`expr $a+$b`
echo $c----1311465600> this output i will use this value to delete the data from MySQL db
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whats wrong with this addition?
Whats the maximum number of digits can be handled?
pandeeswaran@ubuntu:~/Downloads$ const=201234454654768979799999
pandeeswaran@ubuntu:~/Downloads$ let new+=const
pandeeswaran@ubuntu:~/Downloads$ echo $new
-2152890657037557890
pandeeswaran@ubuntu:~/Downloads$ (4 Replies)
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Hi
I have a file whose contents are as follows:
sorce1 LEN assumption 695 3570 0.770047 - . ID=f000001.1;source_id=A.off_LEN_10008424;
sorce1 LEN descriptive 3334 3570 . - 0 Parent=f000001.1;
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Discussion started by: sa@@
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EXPR(1) General Commands Manual EXPR(1)
NAME
expr - evaluate arguments as an expression
SYNOPSIS
expr arg ...
DESCRIPTION
The arguments are taken as an expression. After evaluation, the result is written on the standard output. Each token of the expression is
a separate argument.
The operators and keywords are listed below. The list is in order of increasing precedence, with equal precedence operators grouped.
expr | expr
yields the first expr if it is neither null nor `0', otherwise yields the second expr.
expr & expr
yields the first expr if neither expr is null or `0', otherwise yields `0'.
expr relop expr
where relop is one of < <= = != >= >, yields `1' if the indicated comparison is true, `0' if false. The comparison is numeric if
both expr are integers, otherwise lexicographic.
expr + expr
expr - expr
addition or subtraction of the arguments.
expr * expr
expr / expr
expr % expr
multiplication, division, or remainder of the arguments.
expr : expr
The matching operator compares the string first argument with the regular expression second argument; regular expression syntax is
the same as that of ed(1). The (...) pattern symbols can be used to select a portion of the first argument. Otherwise, the
matching operator yields the number of characters matched (`0' on failure).
( expr )
parentheses for grouping.
Examples:
To add 1 to the Shell variable a:
a=`expr $a + 1`
To find the filename part (least significant part) of the pathname stored in variable a, which may or may not contain `/':
expr $a : '.*/(.*)' '|' $a
Note the quoted Shell metacharacters.
SEE ALSO
sh(1), test(1)
DIAGNOSTICS
Expr returns the following exit codes:
0 if the expression is neither null nor `0',
1 if the expression is null or `0',
2 for invalid expressions.
7th Edition April 29, 1985 EXPR(1)