When you're using command substitution with commands that contain single quotes, you need to know that the quoting rules change. $(...) is almost always easier to get right without having to think about it too much as opposed to `...`.
The command:
Hi,
I have input with decimal point ( 9.99 ) for hours variable hrs.
I need to change it to seconds.
Here is my code:
secs=`/usr/ucb/echo $hrs*3600 |bc`
But I don't want to see the decimal point.
I can use awk to trim it if there is one.
I am just wondering if there is better standard... (2 Replies)
Hi all. Using /bin/sh on an HPUX system.
I want to place a decimal in the field 2 charactors from the right (yes, converting to currency). The field lengths are variable. Here's what I'm doing:
exec < filename
while read FIELD1 FIELD2
do
FIELD1="echo $FIELD1 | sed 'syntax that will... (4 Replies)
Hi
In Unix, I have a file with some numbers like :
45600
12345
I want to insert a decimal point for these numbers based on user input.
If the input is 2, the numbers should be changed to
456.00
123.45
If the input is 3, the numbers should be changed to
45.600
12.345
Can... (2 Replies)
Hi everyone,
I am new here and generally not experienced with linux. My question must be easy, but as for now I have no idea how to do it.
I have lots of directories with numerical names, e.g. 50 50.1 50.12 etc. What I want is to leave directories with no or single digit after the decimal... (2 Replies)
hi there I being trying to figure out way to add " .0" to an integer value in a csv using sed or awk with out success. just as a work around for 2147483647 32 bit limitation that influxdb is currently having
the data base will accept values and work fine if it has the XXX.0 ... (7 Replies)
Hello,
I have often found bash to be difficult when it comes to floating point numbers. I have data with rows of tab delimited floating point numbers. I need to find the smallest number in each row that is not 0.0. Numbers can be negative and they do not come in any particular order for a given... (9 Replies)
Hi , I have a file which contains text like
A|Mau|Code|12|Detail
B|Mau|Code|20|Header
I want to write a command using awk which will output
A|Mau|Code|12.00|Detail
B|Mau|Code|20.00|Header
I used a command like awk -F"|" {printf "%s|%s|%s|%.2f|%s",$1,$2,$3,$4,$5}' which does the... (4 Replies)
Discussion started by: LoneRanger
4 Replies
LEARN ABOUT OSF1
apply
apply(1) General Commands Manual apply(1)NAME
apply - Applies a command to a set of arguments
SYNOPSIS
apply [-acharacter] [-number] command argument...
The apply command runs the specified command on each argument in turn.
OPTIONS
Identifies the character used instead of the % (percent sign) to designate argument substitution strings. Specifies the number of argu-
ments to be passed to command.
DESCRIPTION
Normally, arguments are chosen individually; the optional number specifies the number of arguments to be passed to command. If number is 0
(zero), command is run without arguments once for each argument.
If you include character sequences of the form %n (where n is a digit from 1 to 9) in command, they are replaced by the nth unused argument
following command when command is executed. If any such sequences occur, number is ignored, and the number of arguments passed to command
is the maximum value of n in command.
You can specify a character other than % (percent sign) to designate argument substitution character strings with the -a option; for exam-
ple, -a@ would indicate that the sequences @1 and @2 were to be replaced by the first and second unused arguments following command.
NOTES
Shell metacharacters in command may have undesirable effects; it is best to enclose complicated commands in ' ' (single quotes).
There is no way to pass a % (percent sign) followed immediately by any number if % is the argument expansion character.
EXAMPLES
The following command is similar to ls: apply echo * The following command compares the file a1 to the file b1, a2 to b2, and so on: apply
-2 cmp a1 b1 a2 b2 ... The following command runs who 5 times: apply -0 who 1 2 3 4 5 The following command links all files in the current
directory to the directory /usr/joe: apply 'ln %1 /usr/joe' *
SEE ALSO
Commands: sh(1), xargs(1)apply(1)