Hi All,
I came across a bit of code that seems to work, even though I didn't expect it to (now that's wierd!)
#!/bin/sh
set -x
nn=15
if
then
echo "is true"
fi
The above code ends up comparing the string "nn" to number 15, but still evaluates to true. Here's the output when i run it... (1 Reply)
Hi,
i want to print the mail exchange servers for a domain using the code below, the problem is that i just get the memory locations (?) of the elements in the output, instead of the mx servers.
I really tried to find a solution, but i guess that i just don't get it (objects, OOP etc).. :)
... (2 Replies)
// Hello all,
I am having this error "Dereferencing pointer to incomplete type " on these 2 lines:
xpoint = my_point->x;
ypoint = my_point->y;
I am having no clue y this is happening.
Any help would be greately appreciated!!!!
#include<stdio.h>
#include<string.h>... (2 Replies)
Hi,
This should be a simple one.
All I am doing is adding an email address to my email.
Example abc@xyz.com
I understand that the @ means arrays in PERL. So, I coded the backtick (`) to dereference it. But now I get abc`@`xyz.com
Your help is appreciated.
Thanks
Nurani (2 Replies)
Hi there, I am trying to dereference my hash of hashes but post dereferencing, it seems to lose its structure I am using Data::dumper to help me anaylise.
This is the code im using to build the HoH, (data comes from a file). I have also performed a Dumper on the data structure before and after... (1 Reply)
Simple enough problem I think, I just can't seem to get it right.
The below doesn't work as intended, it's just a function defined in a much larger script:
CheckValues() {
for field in \
Group_ID \
Group_Title \
Rule_ID \
Rule_Severity \
... (2 Replies)
I have a group of variables myLINEcnt1 - myLINEcnt10. I'm trying to printout the values using a for loop. I am at the head banging stage since i'm sure it has to be a basic syntax issue that i can't figure out.
For myIPgrp in 1 2 3 4 5 6 7 8 9 10; do
here i want to output the value of... (4 Replies)
Hello All,
Maybe I'm Missing something here but I have NOOO idea what the heck is going on with this....?
I have a Variable that contains a PATTERN of what I'm considering "Illegal Characters". So what I'm doing is looping
through a string containing some of these "Illegal Characters". Now... (5 Replies)
Hi All,
I have a file which has hundred of records with fixed number of fields. In each record there is set of 8 characters which represent the duration of that activity. I want to sum up the duration present in all the records for a report. The problem is the duration changes per record so I... (5 Replies)
Hi guys
I am trying to dereference a variable inside 'egrep -v ' command and getting a 'egrep: syntax error' :
$ echo $exclude_list
ts584d hf584db
for i in `echo $exclude_list`; do
egrep -v ${i} my_file
done
egrep: syntax error
egrep: syntax error
The syntax of the loop is correct.... (1 Reply)
Discussion started by: aoussenko
1 Replies
LEARN ABOUT ULTRIX
expr
expr(1) General Commands Manual expr(1)Name
expr - evaluate expressions
Syntax
expr arg...
Description
The arguments are taken as an expression. After evaluation, the result is written on the standard output. Each token of the expression is
a separate argument.
The operators and keywords are listed below. The list is in order of increasing precedence, with equal precedence operators grouped.
expr | expr Yields the first expr if it is neither null nor 0. Otherwise yields the second expr.
expr & expr Yields the first expr if neither expr is null or 0. Otherwise yields 0.
expr relop expr The relop is one of < <= = != >= > and yields 1 if the indicated comparison is true, '0' if false. The comparison is
numeric if both expr are integers, otherwise lexicographic.
expr + expr
expr - expr
Yields addition or subtraction of the arguments.
expr * expr
expr / expr
expr % expr
Yields multiplication, division, or remainder of the arguments.
expr : expr The matching operator compares the string first argument with the regular expression second argument; regular expres-
sion syntax is the same as that of The (...) pattern symbols can be used to select a portion of the first argument.
Otherwise, the matching operator yields the number of characters matched ('0' on failure).
( expr ) parentheses for grouping.
Examples
The first example adds 1 to the Shell variable a:
a=`expr $a + 1`
The second example finds the file name part (least significant part) of the pathname stored in variable a,
expr $a : '.*/(.*)' '|' $a
Note the quoted Shell metacharacters.
Diagnostics
The command returns the following exit codes:
0 The expression is neither null nor '0'.
1 The expression is null or '0'.
2 The expression is invalid.
See Alsoed(1), sh(1), test(1)expr(1)