print - for printing whole line, but delimeters are changed to spaces
Hi consider the source file
using the print statement in awk prints it as
Is there an easier way to print the whole line in its original format (i.e. with | delimiters) than doing print $1"|"$2"|"$3 ??
hello,
i have a file "TEST" and want to change the digit(s) after "=" . but i also want to print the old entry with a comment (for information).
i want to use "sed", is it possible ?
file:
TEST = 10 # comment default value: 0
sed , with "p" , i can print the old entry, but i want to... (2 Replies)
Hi,
I have a problem where I need to append few spaces(say 10 spaces) for each line in a file whose length is say(100 chars) and others leave as it is.
I tried to find the length of each line and then if the length is say 100 chars then tried to write those lines into another file and use a sed... (17 Replies)
Hi All
I've a file which is similar to the one given below
column1 coulmn2 column3 column4
A B C D
X Y
F G H
I would like to get it in this format
A|B|C|D
||X|Y
F||G|H
Is... (4 Replies)
awk '/abc/{print $2}'
This will show the line contains abc and only show the "two filed"
But I want to the line contains "abc" will only show $2, other line still show.
and I want to know awk's way about not only show the line besides changed line
Thanks (2 Replies)
Hi,
I need help to split any lines that contain ; or ,
input.txtAc020 Not a good chemical process
AC030 many has failed, 3 still maintained
AC040 Putative; epithelial cells
AC050 Predicted binding activity
AC060 rodC Putative; upregulated in 48;h biofilm vs planktonic
The output... (8 Replies)
I seem to have hit a curious problem where sed and awk based regex do not seem to work. Perhaps I am missing a switch to look within the same line and not across lines.
I have input as follows:
... (4 Replies)
Hi,
Need to sort file based on the number of delimeters in the lines.
cat testfile
/home/oracle/testdb
/home
/home/oracle/testdb/newdb
/home/oracle
Here delimeter is "/"
expected Output:
/home/oracle/testdb/newdb
/home/oracle/testdb
/home/oracle
/home (3 Replies)
when given a file name, im looking for the most efficient way to turn each letter of the file name into spaces.
for instance, the way im thinking of going about this is this:
MYFILE=check_disks.sh
CHANUM=$(echo ${MYFILE} | awk '{ print length }')
printf '%s\n' $CHANUM
as you can see... (4 Replies)
Discussion started by: SkySmart
4 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)