awk formatting Post: 302617739

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Let's say I write a simple script that contains the following: date | awk '{print $1}' date | awk '{print $2}' Of course, when I run the script the output will look similar to: Tue Mar What if I want my ouput to be on one line as follows: Tue Mar What changes would I need to...

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I have a file in CSV format (2 columns ID and Number of Items): AB1 ,,10 AB2 ,,20 AB2 ,, 30 AB3 ,, 10 AB4 ,, 20 AB4 ,, 30 AB4 ,, 40 AB5 ,, 50 AB6 ,, 10 AB7 ,, 20 AB7 ,, 30 AB7 ,, 40 ...... This file is produced daily i would like to get it in the following format, so...

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Hello, I have got the following kine in my script awk '{printf("%s,", $0);next}{printf("%s", $0)}' ORS="," a.txt > b.out The contents of b looks somewaht like this: QUEUE(QUEUE1.Q),CURDEPTH(0),QUEUE(QUEUE2.Q),CURDEPTH(0),QUEUE(QUEUE3.Q),CURDEPTH(0) But my desired output is :...

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output formatting with awk.

# echo $PATH /usr/kerberos/sbin:/usr/kerberos/bin:/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin:/root/bin How would i write a script to display permission on each folders in $PATH variable below format. drwxr-xr-x 2 0 root 4096 Nov 24 14:51 /usr/kerberos/sbin drwxr-xr-x 2 0...

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Hi I have a file as given below: <table border=1> <TR><TH>Script Name</TH><TH>CVS Status</TH><TH>Script Location</TH></TR> <TR><TD><CENTER>Work Area: /home/ustst/</CENTER></TD></TR> <TR><TD><CENTER>admin_export.sh</CENTER></TD><TD><CENTER>Locally...

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Dear all I require help with AWK regarding this situation Input is : fn1 12345 fn1 23456 fn3 231513 fn1 22325 fn3 123125 Desired output is fn1 12345 23456 22325 fn3 231513 123125

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Hi all, Below is my testfile: COST,31-MAR-2011 01:01:04,31-MAR-2011 11:22:12,622 COST,21-MAR-2011 22:00:20,22-MAR-2011 11:07:23,788 FARE,23-MAR-2011 22:00:22,24-MAR-2011 10:10:46,731 FARE,02-MAR-2011 14:01:50,03-MAR-2011 08:30:54,1110 I need to append a number, for example 700, to the...

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formatting awk

when i try this awk its giving out put as below. awk '!(/^$/||/--/||/selected/||/^ *$/){print $1}' tmp.txt output ===== 1 2010-08-03-12.31.26.126000 how excluede the 1st line ? i mean i want output only 2nd line i.e 2010-08-03-12.31.26.126000;

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Formatting a report using awk

Our vendor produces a report that I would like to format in a particular way. Here is the sample output from their report: # AA.INDEX 2 11 2 239 52 (7,2) 07 MAY 11 203.1 55 # ACCOUNT 2 89561 2 ...

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Suffix formatting with awk

i would like to format the 9 character with suffix as "0". i tried below it doesn't work. >a=12345 > echo $a | awk '{printf "%-09s\n",$1}' >12345 required output is 123450000 can you guys help me out ?

LEARN ABOUT DEBIAN

zcmp

ZDIFF(1)						      General Commands Manual							  ZDIFF(1)

NAME

       zcmp, zdiff - compare compressed files

SYNOPSIS

       zcmp [ cmp_options ] file1 [ file2 ]
       zdiff [ diff_options ] file1 [ file2 ]

DESCRIPTION

       Zcmp  and  zdiff are used to invoke the cmp or the diff program on files compressed via gzip.  All options specified are passed directly to
       cmp or diff.  If only file1 is specified, it is compared to the uncompressed contents of file1.gz.  If two files are specified, their  con-
       tents  (uncompressed  if  necessary)  are  fed to cmp or diff.  The input files are not modified.  The exit status from cmp or diff is pre-
       served.

SEE ALSO

       cmp(1), diff(1), zmore(1), zgrep(1), znew(1), zforce(1), gzip(1), gzexe(1)

BUGS

       Messages from the cmp or diff programs may refer to file names such as "-" instead of to the file names specified.

																	  ZDIFF(1)

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