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Top Forums Shell Programming and Scripting $0 doesn't have full directory path Post 302591462 by gary_w on Thursday 19th of January 2012 02:08:56 PM
Old 01-19-2012
Exactly, that is why you want to strip out the path part of $0 by using basename first.
 

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BASENAME(3)								 1							       BASENAME(3)

basename - Returns trailing name component of path

SYNOPSIS
string basename (string $path, [string $suffix]) DESCRIPTION
Given a string containing the path to a file or directory, this function will return the trailing name component. PARAMETERS
o $path - A path. On Windows, both slash ( /) and backslash ( ) are used as directory separator character. In other environments, it is the forward slash ( /). o $suffix - If the name component ends in $suffix this will also be cut off. RETURN VALUES
Returns the base name of the given $path. EXAMPLES
Example #1 basename(3) example <?php echo "1) ".basename("/etc/sudoers.d", ".d").PHP_EOL; echo "2) ".basename("/etc/sudoers.d").PHP_EOL; echo "3) ".basename("/etc/passwd").PHP_EOL; echo "4) ".basename("/etc/").PHP_EOL; echo "5) ".basename(".").PHP_EOL; echo "6) ".basename("/"); ?> The above example will output: 1) sudoers 2) sudoers.d 3) passwd 4) etc 5) . 6) NOTES
Note basename(3) operates naively on the input string, and is not aware of the actual filesystem, or path components such as " ..". Note basename(3) is locale aware, so for it to see the correct basename with multibyte character paths, the matching locale must be set using the setlocale(3) function. SEE ALSO
dirname(3), pathinfo(3). PHP Documentation Group BASENAME(3)
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