my file looks like this:
101928 101943
101928 101944
101929 101943
101929 101943
101929 102044
i want to insert bc to get answer like this:
101928 101943 000015
101928 101944 000016
101929 101943 000013
101929 101943 000014
101929 102044 000115
total 000173
my... (3 Replies)
Hello people,
awk '{print $0}' input1.txt input2.txt |sort -u
Will give the union of the 2 files. Similarly what is command to get just the diff data (i.e minus) of the 2 files. Can I use the "diff" command to get just the diff data.
Please let me know.
Regards,
Tipsy. (7 Replies)
I need to rename a directory full of files named like:
page_001.jpg
page_002.jpg
page_003.jpg
to the file name minus one. Meaning instead of page_001.jpg that file becomes page_000.jpg so:
page_001.jpg => page_000.jpg
page_002.jpg => page_001.jpg
page_003.jpg => page_002.jpg
I was... (3 Replies)
In Redhat it is easy....
date --date="60 minutes ago"
How do you do this in Solaris?
I got creative and got the epoch time but had problems..
EPOCHTIME=`truss date 2>&1 | grep "time()" | awk '{print $3 - 900}'`
echo $EPOCHTIME
TIME=`perl -e 'print scalar(localtime("$EPOCHTIME")),... (5 Replies)
Hi there,
I have a problem with arithmetic ops in awk.
Here is what my script does right now.
while read nr val ; do
case $nr in
400) awk '$2~/eigenvectors/ {print $NF-'$val'};' input.txt >> output.txt;;
esac
done < frames.txtI have a file named frames.txt with two columns (nr and... (2 Replies)
Hi,
I need to subtract 5 minutes from the date. Example
$date +"%Y-%m-%d-%H.%M.%S" displays 2014-06-26-06.06.38
I want to show it as 2014-06-26-06.01.38 (5 mins are subtracted from date)
Any help would be appreciated. I am currently on AIX version 6.1
-Vrushank (10 Replies)
Hi the below code is failing i am trying to generate do the following:
2014-10-22 11:26:00 (Substract 24 hrs)
should produce
2014-10-21 11:26:00
I need the same formatting below because that gets inputted into code for an... (4 Replies)
Hello,
date --date '-60 min ago' +'%Y-%m-%d %H:%M:%S,%3N'
Above command gives the date and time minus 60 minutes
but the problem i am facing is, i do not want to hardcode the value 60
it is stored in a variable var=60
now if i run below command , i get error
date --date '-$var min... (3 Replies)
Hello Folks,
I have a variable output holding date as below -
output = "20141220"
I need to extract a day out of it and store it in another variable i.e. something similar to below -
output1=20141219"
and if the month is changing i.e. date in on 31st or 1st it should be taken care of
"date... (5 Replies)
Discussion started by: ektubbe
5 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)