Re ordering lines - Awk Post: 302543740

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Top Forums Shell Programming and Scripting Re ordering lines - Awk Post 302543740 by quincyjones on Tuesday 2nd of August 2011 01:45:02 AM

08-02-2011

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Re ordering lines - Awk

Is it possible to re-order certain rows as columns (of large files).
Few lines from the file for reference.

input

Code:

Splicing Factor: Tra2beta, Motif: aaguguu, Cutoff: 0.5000
Sequence Position	Genomic Coordinate	K-mer     	Score   
97               	chr1:67052604     	uacuguu   	0.571   
147              	chr1:67052554     	augugua   	0.536   
166              	chr1:67052535     	aaauuuu   	0.500   
226              	chr1:67052475     	aauugug   	0.612   
Splicing Factor: SRp20, Motif: wcwwc, Cutoff: 0.7200
Sequence Position	Genomic Coordinate	K-mer     	Score   
302              	chr1:67052399     	ucauc     	0.875   
349              	chr1:67052352     	acauc     	0.740

output

Code:

Splicing_Factor	Motif	Cutoff	Sequence_Position	Genomic_Coordinate	K-mer	Score   
Tra2beta	aaguguu	0.5000	97	chr1:67052604     	uacuguu   	0.571
Tra2beta	aaguguu	0.5000	147	chr1:67052554     	augugua   	0.536
Tra2beta	aaguguu	0.5000	166	chr1:67052535     	aaauuuu   	0.500 
Tra2beta	aaguguu	0.5000	226	chr1:67052475     	aauugug   	0.612
SRp20	wcwwc	0.7200	302	chr1:67052399	ucauc	0.875   
SRp20	wcwwc	0.7200	349	chr1:67052352	acauc	0.740

Last edited by quincyjones; 08-02-2011 at 02:52 AM..

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LEARN ABOUT DEBIAN

bup-margin

bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME

       bup-margin - figure out your deduplication safety margin

SYNOPSIS

       bup margin [options...]

DESCRIPTION

       bup margin  iterates  through  all  objects  in	your  bup repository, calculating the largest number of prefix bits shared between any two
       entries.  This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.

       For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45.  That  means  a  46-bit
       hash  would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
       its first 46 bits.

       The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects.  Since SHA-1 hashes have 160 bits,
       that  leaves 115 bits of margin.  Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
       with far fewer objects.

       If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see	if
       you're getting dangerously close to 160 bits.

OPTIONS

       --predict
	      Guess  the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
	      from the guess.  This is potentially useful for tuning an interpolation search algorithm.

       --ignore-midx
	      don't use .midx files, use only .idx files.  This is only really useful when used with --predict.

EXAMPLE

	      $ bup margin
	      Reading indexes: 100.00% (1612581/1612581), done.
	      40
	      40 matching prefix bits
	      1.94 bits per doubling
	      120 bits (61.86 doublings) remaining
	      4.19338e+18 times larger is possible

	      Everyone on earth could have 625878182 data sets
	      like yours, all in one repository, and we would
	      expect 1 object collision.

	      $ bup margin --predict
	      PackIdxList: using 1 index.
	      Reading indexes: 100.00% (1612581/1612581), done.
	      915 of 1612581 (0.057%)

SEE ALSO

       bup-midx(1), bup-save(1)

BUP

       Part of the bup(1) suite.

AUTHORS

       Avery Pennarun <apenwarr@gmail.com>.

Bup unknown-															     bup-margin(1)