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Top Forums Shell Programming and Scripting Passing value as a command line argument in awk script. Post 302541525 by humaemo on Monday 25th of July 2011 03:38:43 AM
Old 07-25-2011
Passing value as a command line argument in awk script.

I have one working awk command line. Which taking data from the “J1202523.TXT” file and generating the “brazil.dat” file. PFB code.
Code:
awk '{ DUNS = substr($0,0,9);if ( substr($0,14,3) == "089" ) print DUNS }' J1202523.TXT > Brazil.dat

But now I want to pass two parameter as a command line argument .
1. 089
2. brazil
Please help me how can I pass command line parameter in awk script.

Last edited by radoulov; 07-25-2011 at 06:32 AM.. Reason: Code tags.
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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