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Full Discussion: Help with variable substition in sed
Top Forums UNIX for Dummies Questions & Answers Help with variable substition in sed Post 302529787 by Corona688 on Friday 10th of June 2011 11:33:18 AM
Old 06-10-2011
Probably because of the /'s mucking things up. It sees an unescaped / and thinks the expression ought to end there, finds more junk after it and throws a syntax error. Use another char as sed's separator:
Code:
sed -e "#/home/fred/scripts#d"

You should be able to substitute variables directly into that.

I'd just use grep, though:
Code:
grep -v "/home/scripts/fred" < infile > outfile

This User Gave Thanks to Corona688 For This Post:
derndingle
 

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LEARN ABOUT ULTRIX

zgrep

ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep	options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

																	  ZGREP(1)
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