Hi Everybody,
Can you explain the difference between the following commands:
1. find . -print|xargs grep -i dba_2pc_pending
2. find . -print|grep -i dba_2pc_pending (5 Replies)
Hello,
I'm on a mac trying to have the follow cmd list the files after touch, but very unsuccessful. Please can you help.
sort $BOTHFILE | uniq -u | xargs -I {} -t touch {} >> $LOGFILE ;
BOTHFile contents in form of
/directory/file.txt
thanx (3 Replies)
my task : tar up large bunch of files(about 10,000 files) in the current directories that created more than 30 days ago
but it come with following error
find ./ -ctime +30 | xargs tar rvf test1.tar
tar: test1.tar: A file or directory in the path name does not exist. (3 Replies)
what is the real use of xargs command ..?
ls -tr |xargs -I{} rm -f {}
....can any one tell me what is the significance of {} curly brackets in this command (1 Reply)
Hi
I am trying to use "xargs" command to loop through each file, modify it and overwrite the old file with the modification but with the same file name.
I thought it is easy but I just can't get it to work
I tried the following
I thought {} would give me the current file name, but it... (1 Reply)
Hi,
What is the difference in capitalizing the option 'i' of xargs command, (i.e) xargs -i and xargs -I?
Also, what is the difference between the below 2 commands?
output_from_cmd | xargs -I {} grep '{}' file
output_from_cmd | xargs -I grep '{}' file
Any efficiency or performance... (4 Replies)
ls -lrt | awk '$7==12{print $9}' | xargs -i mv {} $dir
i executed this command but $dir does not exists.......
and the files hv been moved but i dont know where .....
plz help(ASAP)
thanks in advance. (8 Replies)
xargs work great when a command gives multiple line output which can be input to another. In my case it is not working coz the second command uses two words in it.
$ scr.sh
gives output like
193740
638102
375449
..
..
another command takes these number as inputs. it works great... (1 Reply)
ls | grep -E '^+$' | xargs --verbose -I{} rm -vfr "{}";
When i execute the command it works fine by removing the directories and its writing the output as below about which files are deleting.What i want know is,is there any XARGS command option that it should done silently in background with... (2 Replies)
Hi,
I am working on a file copier utility where I have written the copy commands to a batch file e.g. file_copier.bat which i pass to xargs command as follows.
cat file_copier.bat | xargs -n 1 -P 40
I also want to record the copy command status of each file/command in the form "command... (1 Reply)
Discussion started by: ankur singh
1 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)