05-21-2011
Hi,
Could you explain, what is the link between scanning new scsi device and the rw access to / ?
I guess you forgot something in your post so we can understand something, or try to. . .
Anyway here the problem is obviously serious because you can't even execute /bin/mount
So i guess there are some kind of harware problem around here.
10 More Discussions You Might Find Interesting
1. UNIX for Advanced & Expert Users
my partner change the server's ip address and now i can't to mount the oracle's filesystem, what i do? i don't want to reinstall Unix. My unix is SCO UNIX 5.0.5 (9 Replies)
Discussion started by: marun
9 Replies
2. Shell Programming and Scripting
Hi
How can I only print the file systems that are more than 95% full.
I used the df -k output and tried to check for each file system and then print only the ones that meet the criteria... But my solution seems cloodgie ... (3 Replies)
Discussion started by: YS2002
3 Replies
3. Filesystems, Disks and Memory
Dear Experts,
Is it possible to take a backup of two file systems using a single vdump command?
Thanks
Wilson (4 Replies)
Discussion started by: geraldwilson
4 Replies
4. UNIX for Advanced & Expert Users
Dear All
We have HP9000 rp7400 Server running with hp-ux 11i.
Our Disk storage has two volume groups and are allocated as follows:
1. /#vgdisplay -v
--- Volume groups ---
VG Name /dev/vg00
VG Write Access read/write
VG Status available... (1 Reply)
Discussion started by: mhbd
1 Replies
5. AIX
Hi to all
i want to increase the /usr size.
but, it is mirrored on hdisk0 and hdisk1.
i know that chfs will work, but i am not confident about mirroring.
can anyone tell me the procedure.
thanks (2 Replies)
Discussion started by: honeym210
2 Replies
6. UNIX for Dummies Questions & Answers
how to check the record of previously mounted remote filesystems after the filesystems are unmounted .operating system is solaris 10 (0 Replies)
Discussion started by: ravijanjanam12
0 Replies
7. Shell Programming and Scripting
i need to write a shell script for printing the list of filesystems whose disk utilization is more than 75%...i tried using df -h along with awk but cud'nt make the combination work.....:wall:
when we do df -h then the filesystems which are using more than 75% capacity shud be printed according to... (11 Replies)
Discussion started by: xtatic
11 Replies
8. Shell Programming and Scripting
I need a scrip that will show me the filesystems that are greater than 70%...but not sure how to filter using the df -h | grep
Thank you for your help!! (6 Replies)
Discussion started by: eponcedeleonc
6 Replies
9. Solaris
I have two test machines having solaris 10. I have shared a location which have a package on machine1 and mounted that location onto machine2 as below.
machine1: share -F nfs -o rw /home1/pkg/test
machine2: mount -F nfs -o rw machine2:/home1/pkg/test /tmp/test
Now, when i am trying to... (8 Replies)
Discussion started by: snreddy_gopu
8 Replies
10. Red Hat
Hi all,
Today I´m faced a situation where two of my ext3 filesystems on a san become read only. This happens 3 times today.
The usual way to get this filesystems read and write was to reboot the server.
But now the continuous go to ro mode instead of rw mode, crashes my database.
I have... (7 Replies)
Discussion started by: mig28mx
7 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)
NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS
--predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO
bup-midx(1), bup-save(1)
BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown- bup-margin(1)