hi, i have gone thru it.
One of my file contains variable and its value (A to E )
param.ksh
----------
Now this script i am invoking from other shell scropt
here, i need to check that all 5 (A,B,C,D,E) variables should be declared and assigned values to it, in order to proceed further. If any one of the variable is not declared or value is not assigned to it. process should stop and exit
I declared a variable x that gets the count(*) from a table. The table name is also defined as a variable.
What's wrong with this statment :
X=” select count(*) from ${table_name}“
then
y = `${X}${table_name}'
echo ${y}
It throws an error saying count not found.
Please... (1 Reply)
i have variables with different values as below in KSH
AU_Holiday=1
SG_Holiday=0
KR_Holiday=1
JP_Holiday=0
$country_cd is the second variable which be one of 'AU' 'SG' 'KR' 'JP' which comes in a for loop.
form that i need to derive the variable like first one and check whether it is equal... (3 Replies)
Hi all,
How to print variable value which i have assigned inside for loop
because that variable scope is local, but i want to use that variable outside for loop.
Awaiting your great help
Thanks,
Susil (1 Reply)
Dear Unix experts
I want to define a variable which contains dynmic and static part, daynamic part is the first field.
Sample of data
dddd aaaa sssss 12345
ssss 2323 234234 4242
dddd 3223 34234 54353
ssss 24234 3434 42342
dddd rwrw 423423 werwer
nawk 'BEGIN {FS=" "}{... (4 Replies)
Anyone please say what is the difference between $var and ${var} in perl
Sometimes $var used and sometimes ${var} used in same program.
Thanks in Advance,
Prabhu
---------- Post updated at 09:34 AM ---------- Previous update was at 05:59 AM ----------
Any one please clarify (1 Reply)
Dear Unix experts
Moved from "Shell Programming and Scripting "
I want to define a variable which contains dynmic and static part, daynamic part is the first field.
Sample of data
dddd aaaa sssss 12345
ssss 2323 234234 4242
dddd 3223 34234 54353
ssss 24234 3434 42342
dddd rwrw 423423... (2 Replies)
Hello,
Why is this not working in a script?
files="test.fsa"
echo $files
for file in $files
do
if
then
echo "$file does not exist."
fi
run a command
done
I get an error saying (3 Replies)
Discussion started by: verse123
3 Replies
LEARN ABOUT FREEBSD
atf-sh
ATF-SH(1) BSD General Commands Manual ATF-SH(1)NAME
atf-sh [-s shell] -- interpreter for shell-based test programs
SYNOPSIS
atf-sh script
DESCRIPTION
atf-sh is an interpreter that runs the test program given in script after loading the atf-sh(3) library.
atf-sh is not a real interpreter though: it is just a wrapper around the system-wide shell defined by ATF_SHELL. atf-sh executes the inter-
preter, loads the atf-sh(3) library and then runs the script. You must consider atf-sh to be a POSIX shell by default and thus should not
use any non-standard extensions.
The following options are available:
-s shell Specifies the shell to use instead of the value provided by ATF_SHELL.
ENVIRONMENT
ATF_LIBEXECDIR Overrides the builtin directory where atf-sh is located. Should not be overridden other than for testing purposes.
ATF_PKGDATADIR Overrides the builtin directory where libatf-sh.subr is located. Should not be overridden other than for testing purposes.
ATF_SHELL Path to the system shell to be used in the generated scripts. Scripts must not rely on this variable being set to select a
specific interpreter.
EXAMPLES
Scripts using atf-sh(3) should start with:
#! /usr/bin/env atf-sh
Alternatively, if you want to explicitly choose a shell interpreter, you cannot rely on env(1) to find atf-sh. Instead, you have to hardcode
the path to atf-sh in the script and then use the -s option afterwards as a single parameter:
#! /path/to/bin/atf-sh -s/bin/bash
ENVIRONMENT
ATF_SHELL Path to the system shell to be used in the generated scripts.
SEE ALSO atf-sh(3)BSD September 27, 2014 BSD