hi
I wanted to use the for loop structure in tandem with rsh command and the result to be redirected into a local .lst file within a shell script .
Tried the following but does not help :confused: .
rsh ABCD "cd /bosp/local/home/linus/;for i in `ls -ltr | grep ^- | awk {'print $9'}`
do... (4 Replies)
Hey all
I have two scripts, one script containing the guts of my code.
The other simply loops through a list, calling the other script on each iteration.
Problem is when I add the line
`/usr/bin/rsh -l root $HOSTNAME ""`
to my main script, the loop never seems to exectute any more... (1 Reply)
I am a newbie to awk and c programming, however am not a unix newbie. However, I do need help with a kshell script I am writing. It is almost complete, the last step is killing me. Any help would be greatly appreciated. What I am trying to do is cat a text file that has usernames. Then, using... (2 Replies)
Hi,
I've tried searching the forums for a case similar to mine but was unsuccessful. This is my first time to use awk so any help would be really appreciated :)
I have one file containing data for with the first value in each row being a State Name. I would need to create a separate file... (1 Reply)
Hi,
I have a text file with data in that I wish to extract, assign to a variable and process through a loop.
Kind of the process that I am after:
1: Grep the text file for the values.
Currently using:
cat /root/test.txt | grep TESTING= | awk -F"=" '{ a = $2 } {print a}' | sort -u
... (0 Replies)
Hi i have to insert the below line into a specific line number of another file
export MBR_CNT_PRCP_TYPE_CODES_DEL="'01','02','04','05','49','55','UNK'"
I have passed the above line to a variable say ins_line. I have used below command to perform the insert
awk 'NR==3{print "'"${ins_line}"'"}1'... (1 Reply)
Hello,
I'm having some issues getting a home dir from a remote server passed to a variable.
Here is what I have so far:
rsh server "(ls -ld /home*/user | awk '{print \$9}')"
/home3/userThat works fine and brings back what I need.
But when I try to add it to a variable it goes all... (3 Replies)
Hi All,
I am new to AWK programming. I have the following for loop in my awk program.
cat printhtml.awk:
BEGIN
-------- <some code here>
END{
----------<some code here>
for(N=0; N<H; N++)
{
for(M=5; M<D; M++) print "\t" D "";
}
-----
}
... (2 Replies)
Hi,
input:
AAA|1
my script (the function is just an example):
gawk 'BEGIN{FS=OFS="|"}
function repeat(str, n, rep, i){
for(i=1; i<=n; i++)
rep=rep str
return rep
}
{
variable_1=repeat($1,$2)
variable_2=repeat($1,$2+1)
variable_3=repeat($1,$2+3)
... (5 Replies)
Thanks all for taking time out and reading this thread and big Thanks to all who have come forward for rescue.
Background: I have a variable "nbrofcols" that has number of columns from a data file. Now, using this count in for loop, I am trying to get the maximum length of each column present... (7 Replies)
Discussion started by: svks1985
7 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)