Sponsored Content
Top Forums Shell Programming and Scripting Print a field from the previous line Post 302517233 by Indra2011 on Tuesday 26th of April 2011 08:50:47 AM
Old 04-26-2011
Print a field from the previous line

plz help me!!
I have this file ,
Code:
3408   5600
3796   6035
4200   6285
4676      0
  40   1554
 200   1998
 652   2451
 864   2728
1200      0

I want it like if $2==0,replace it with field from the previous line+500
say here the o/p would be like
Code:
3408   5600
3796   6035
4200   6285
4676   6785
  40   1554
 200   1998
 652   2451
 864   2728
1200   3228

thanks in advance

Last edited by Franklin52; 04-26-2011 at 10:22 AM.. Reason: Please use code tags
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Print previous, current and next line using sed

Hi, how can i print the previous, current and next line using sed? current line is the matching line. The following prints all lines containing 'Failure' and also the immediate next line cat $file | sed -n -e '/Failure/{N;p;}' Now, i also want to print the previous line too. Thanks,... (8 Replies)
Discussion started by: ysrinu
8 Replies

2. Shell Programming and Scripting

how Print previous line ..........

HELLO...I wanted to ask you, than sure know unix more than me, as I can obtain the following solution: I have a file with rows of the type: CIAO COME STAI PERCHE COME STAI CIAO COME VA ALLO CHE FACCIAMO ................. I would that if in a line is present the word (for example) " CHE... (9 Replies)
Discussion started by: fabi20
9 Replies

3. Shell Programming and Scripting

Print the previous line

My requirement is that when ever search criteria matchs in log file, the previous line just above the search word as well as search word should be print. sample log file --03-19T11:26 xxx create version "a.sh@@/main/6" "104157 " --03-18T16:01 xxx create version "a.sh@@/main/5" ... (6 Replies)
Discussion started by: jadoo_c2
6 Replies

4. UNIX for Dummies Questions & Answers

Awk to print data from current and previous line

Hi guys, I have found your forum super useful. However, right now I am stuck on a seemingly "simple" thing in AWK. I have two columns of data, the first column in Age (in million years) and the second column is Convergence Rate (in mm/yr). I am trying to process my data so I can use it to... (2 Replies)
Discussion started by: awk_noob_456
2 Replies

5. Shell Programming and Scripting

Compare Field in Current Line with Field in Previous

Hi Guys I have the following file Essentially, I am trying to find the right awk/sed syntax in order to produce the following 3 distinct files from the file above: Basically, I want to print the lines of the file as long as the second field of the current line is equal to the... (9 Replies)
Discussion started by: moutaye
9 Replies

6. Shell Programming and Scripting

awk script -print line when $2 > $2 of previous line

Hi all, From a while loop I am reading a sorted file where I want to print only the lines that have $1 match and $2 only when the difference from $2 from the previous line is > 30. Input would be like ... AN237 010 193019 0502 1 CSU Amoxycillin AN237 080 ... (2 Replies)
Discussion started by: gafoleyo73
2 Replies

7. Shell Programming and Scripting

Replace first field of a line with previous filed of the line

Hi Everyone, I have a file as below: IM2345638,sherfvf,usha,30 IM384940374,deiufbd,usha,30 IM323763822,cdejdkdnbds,theju,15 0,dhejdncbfd,us,20 IM398202038,dhekjdkdld,tj,30 0,foifsjd,u2,40 The output i need is as below IM2345638,sherfvf,usha,30... (4 Replies)
Discussion started by: usha rao
4 Replies

8. Shell Programming and Scripting

Command/script to match a field and print the next field of each line in a file.

Hello, I have a text file in the below format: Source Destination State Lag Status CQA02W2K12pl:D:\CAQA ... (10 Replies)
Discussion started by: pocodot
10 Replies

9. Shell Programming and Scripting

How to print previous line of multiple pattern matched line?

Hello, I have below format log file, Comparing csv_converted_files/2201/9747.1012H67126.5077292103609547345.csv and csv_converted_files/22019/97447.1012H67126.5077292103609547345.csv Comparing csv_converted_files/2559/9447.1012H67126.5077292103609547345.csv and... (6 Replies)
Discussion started by: arvindshukla81
6 Replies

10. AIX

Print nth previous line after match

Please help me print nth line after match awk or sed one line command. (3 Replies)
Discussion started by: sushma123
3 Replies
bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
All times are GMT -4. The time now is 02:02 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy