Hello,
I create a file touch 1201093003 fichcomp
and inside a repertory (which hava a lot of files) I want to list all files created before this file :
find *.* \! -maxdepth 1 - newer fichcomp but this command returned bash: /usr/bin/find: Argument list too long
but i make a filter all... (1 Reply)
When I enter the command below grep appears to be returning a file it shouldn't.
find . -name "*.*" -exec grep "testing" {} /dev/null \;
:tps3Mailfile
./SSI.ksh: # create TECHOUT dummy for test for testing purposes
./ftprimi1.ksh:# before running job in prod... change FTP to go to rimi... (3 Replies)
Hi Pals
I am using this command in my script to find out warnings using fgrep where $log is the log file name, $date is the date to be searching and warnings.list contains list of matching words.
grep "WARNING" $log|grep "$date"|fgrep -vf warnings.list
I want to perform another action... (1 Reply)
HI everyone,
I am trying to use the unix sort command to get a list of numbers sorted in ascending order but having trouble in getting it to work.
An example of this issue would be when i am trying to sort the following three
number each on a different line "1" , "2" and "116" the sort command... (3 Replies)
I have a FILE1.DAT with the following information
21111111110001343 000001004OLF-AA029100020091112
21111111110000060 000001004ODL-CH001000020091112
24444444440001416 000001045OLF-AA011800020091112
23333333330001695 000001039OLF-AA030600020091112
23333333330000111... (5 Replies)
Hy guys. My English is not so good, sorry for any mistakes.
I'm a bigginer in C, and I have a problem. I want to sort ascending n strings, but I can't read the strings. Here is what I've done so far:
//sort ascending n strings
#include <stdio.h>
int main()
{
int n,i,j;
char a;
... (8 Replies)
Hi,
i had a data block (coming from pipe from other codes) as:
H YF_CO.dat 77164 11/17/2013 04:00:02 731374590.96 1 1 731374590.96 76586 77164 578 2988 Y
H YF_CO.dat 77164 11/17/2013 04:00:07 731374590.96 1 4 731374590.96 76586 77164 578 2988 Y
H YF_CO.dat 77178 ... (5 Replies)
Discussion started by: pr5439
5 Replies
LEARN ABOUT DEBIAN
io::async::timer::absolute
IO::Async::Timer::Absolute(3pm) User Contributed Perl Documentation IO::Async::Timer::Absolute(3pm)NAME
"IO::Async::Timer::Absolute" - event callback at a fixed future time
SYNOPSIS
use IO::Async::Timer::Absolute;
use POSIX qw( mktime );
use IO::Async::Loop;
my $loop = IO::Async::Loop->new;
my @time = gmtime;
my $timer = IO::Async::Timer::Absolute->new(
time => mktime( 0, 0, 0, $time[4]+1, $time[5], $time[6] ),
on_expire => sub {
print "It's midnight
";
$loop->stop;
},
);
$loop->add( $timer );
$loop->run;
DESCRIPTION
This subclass of IO::Async::Timer implements one-shot events at a fixed time in the future. The object waits for a given timestamp, and
invokes its callback at that point in the future.
For a "Timer" object that waits for a delay relative to the time it is started, see instead IO::Async::Timer::Countdown.
EVENTS
The following events are invoked, either using subclass methods or CODE references in parameters:
on_expire
Invoked when the timer expires.
PARAMETERS
The following named parameters may be passed to "new" or "configure":
on_expire => CODE
CODE reference for the "on_expire" event.
time => NUM
The epoch time at which the timer will expire.
Once constructed, the timer object will need to be added to the "Loop" before it will work.
Unlike other timers, it does not make sense to "start" this object, because its expiry time is absolute, and not relative to the time it is
started.
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2012-10-24 IO::Async::Timer::Absolute(3pm)