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Top Forums Programming question about function object Post 302497011 by homeboy on Wednesday 16th of February 2011 04:24:34 AM
Old 02-16-2011
question about function object

I have a code as following:
Code:
#include <iostream>
#include <algorithm>
#include <list>
using namespace std;

//the class Nth is a predicates
class Nth{
    private:
         int nth;
         int count;
    public:
         Nth(int n):nth(n),count(0){}
         bool operator()(int){
             return ++count == nth;
        }
};

int main()
{
       list<int> lst;
 
       for(int i=1;i<10;i++)
           lst.push_back(i);

       copy(lst.begin(),lst.end(),ostream_iterator<int>(cout," "));
       cout<<endl;

       list<int>::iterator pos = remove_if(lst.begin(),lst.end(),Nth(3));
       lst.erase(pos,lst.end());

       copy(lst.begin(),lst.end(),ostream_iterator<int>(cout," "));
       cout<<endl;
}

the output is:
1 2 3 4 5 6 7 8 9
1 2 4 5 7 8 9
Not as I expect:
1 2 3 4 5 6 7 8 9
1 2 4 5 6 7 8 9
The book explained:
This happens because the usual implementation of the algorithm copies the predicate internally during the algorithm:
Code:
template<class ForwIter,class Predicate>
ForwIter std::remove_if(ForwIter beg,ForeIter end,Predicate op)
{
       ForwIter pos = find_if(beg,end,op);
       if(pos == end)
            return beg;
       else{
            ForwIter next = beg;
            return remove_copy_if(++next,end,beg,op);
       }
}

and it says it is possible to avoid this surprise behavior like this:
Code:
template<class ForwIter,class Predicate>
ForwIter std::remove_if(ForwIter beg,ForeIter end,Predicate op)
{
       while(beg != end && !op(*beg))
            beg++;
       if(pos == end)
            return beg;
       else{
            ForwIter next = beg;
            return remove_copy_if(++next,end,beg,op);
       }
}

I don't know what the difference between the two implementations is.I think i was able to understand the first one,but why the second one works fine?I thought they were the same.Any help will be appreciated.
 

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PAPS(1) 						      General Commands Manual							   PAPS(1)

NAME
paps - UTF-8 to PostScript converter using Pango SYNOPSIS
paps [options] files... DESCRIPTION
paps reads a UTF-8 encoded file and generates a PostScript language rendering of the file. The rendering is done by creating outline curves through the pango ft2 backend. OPTIONS
These programs follow the usual GNU command line syntax, with long options starting with two dashes (`-'). A summary of options is included below. --landscape Landscape output. Default is portrait. --columns=cl Number of columns output. Default is 1. Please notice this option isn't related to the terminal length as in a "80 culums terminal". --font=desc Set the font description. Default is Monospace 12. --rtl Do right to left (RTL) layout. --paper ps Choose paper size. Known paper sizes are legal, letter and A4. Default is A4. Postscript points Each postscript point equals to 1/72 of an inch. 36 points are 1/2 of an inch. --bottom-margin=bm Set bottom margin. Default is 36 postscript points. --top-margin=tm Set top margin. Default is 36 postscript points. --left-margin=lm Set left margin. Default is 36 postscript points. --right-margin=rm Set right margin. Default is 36 postscript points. --gutter-width=gw Set gutter width. Default is 40 postscript points. --help Show summary of options. --header Draw page header for each page. --markup Interpret the text as pango markup. --lpi Set the lines per inch. This determines the line spacing. --cpi Set the characters per inch. This is an alternative method of specifying the font size. --stretch-chars Indicates that characters should be stretched in the y-direction to fill up their vertical space. This is similar to the texttops behaviour. AUTHOR
paps was written by Dov Grobgeld <dov.grobgeld@gmail.com>. This manual page was written by Lior Kaplan <kaplan@debian.org>, for the Debian project (but may be used by others). April 17, 2006 PAPS(1)
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