Hello,
this thread is more about scripting style than a specific issue.
I've to grep from a output some lines and from them obtain a specific entry delimited by < and >.
This is my way :
Code:
1) grep -i user list | awk '{FS="<";print $NF}' | sed -e 's/>//g'
2) grep -i user list | cut -d"," -f 3 | cut -d '<' -f 2 | sed -e 's/>//g'
Now, I want to know if there is a best way (sure there is ) to do it.
Moreover, it is possible to put all instruction on a awk cmd ?
br/gb
--------------------------------
UPDATE -
A third way solution :
Code:
grep -i user list | awk -F"[<,>]" '/>/{print $(NF-1)}'
It is fine... but not complete, cause NF is a blanck char. How to del this char from awk test ?
Last edited by gogol_bordello; 01-27-2011 at 10:20 AM..
Hello,
I need use comma and spaces as field delimiters, but I can't:
text:
hello myfriend,I need,some help
I need something like:
awk -F"<blank>|," '{print $1, $3}'
Thanks (3 Replies)
I have the following string sample:
bla bla bla bla bla
I would like to extract the "123" using awk.
I thought about awk -F"]" '{ print $1 }' but it doesn't work
Any ideas ? (7 Replies)
hi,
i have a file called file1.txt and it's contents are as below:
file1.txt:
-------
abc,123, thomas
dab,234,muller
gab,456,ram
The lookup file's contents are as below:
lookup.txt
----------
abc|japan
dcd|US
dab|china
gab|brazil (3 Replies)
Line from input file
a : b : c " d " e " f : g : h " i " j " k " l
output
k b a
Its taking 7th word when " is the delimiter, 2nd and 1st word when : is the delimiter and returning all in one line.... I am on solaris
Thanks..... (1 Reply)
I have a file having lines like:
14: <a="b" val="c"/>
18: <a="x" val="d"/>
54: <a="b" val="c"/>
58: <a="x" val="e"/>
I need to create a file with output:
14
d
54
e
So basically, for every odd line I need 1st word if delimiter is ':' and for every even... (14 Replies)
Hi Folks,
This is the first time I ever encountered this situation
My input file is of this kind
cat input.txt
1 PAIXAF 0 1 1 -9 0 0 0 1 2 0 2 1 2 1
7 PAIXEM 0 7 1 -9 1 0 2 0 1 2 2 1 0 2
9 PAKZXY 0 2 1 -9 2 0 1 1 1 0 1 2 0 1
Till the sixth column (which is -9), I want my columns to... (4 Replies)
What to know the way to count the number of delimiters in each record by ignoring the escape delimiters.
Sample Data:
12345678|ABN\|XYZ MED CHEM PTY. LTD.|C||100.00|22|AB"C\|Corp|"XYZ|CDEF"|
I'm using awk -F'|' '{ print NF-1 }' command to find the number of delimiters. this command... (8 Replies)
I have a file which is separated by delimiter "|", but the prob is one of my column do contain delimiter as description so how can i differentiate it?
PS : the delmiter does have backslash coming before it, if occurring in column
Annual|Beleagured|Desc|Denver... (2 Replies)
Discussion started by: nikhil jain
2 Replies
LEARN ABOUT NETBSD
zgrep
ZGREP(1) BSD General Commands Manual ZGREP(1)NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files
SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...]
zegrep [grep-flags] [--] pattern [file ...]
zfgrep [grep-flags] [--] pattern [file ...]
DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1).
The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern
argument.
zegrep calls egrep(1), while zfgrep calls fgrep(1).
EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0.
SEE ALSO egrep(1), fgrep(1), grep(1), gzip(1), zcat(1)AUTHORS
Thomas Klausner <wiz@NetBSD.org>
BSD December 28, 2003 BSD
01-27-2011
) to do it.