Hello,
this thread is more about scripting style than a specific issue.
I've to grep from a output some lines and from them obtain a specific entry delimited by < and >.
This is my way :
Code:
1) grep -i user list | awk '{FS="<";print $NF}' | sed -e 's/>//g'
2) grep -i user list | cut -d"," -f 3 | cut -d '<' -f 2 | sed -e 's/>//g'
Now, I want to know if there is a best way (sure there is ) to do it.
Moreover, it is possible to put all instruction on a awk cmd ?
br/gb
--------------------------------
UPDATE -
A third way solution :
Code:
grep -i user list | awk -F"[<,>]" '/>/{print $(NF-1)}'
It is fine... but not complete, cause NF is a blanck char. How to del this char from awk test ?
Last edited by gogol_bordello; 01-27-2011 at 10:20 AM..
Hello,
I need use comma and spaces as field delimiters, but I can't:
text:
hello myfriend,I need,some help
I need something like:
awk -F"<blank>|," '{print $1, $3}'
Thanks (3 Replies)
I have the following string sample:
bla bla bla bla bla
I would like to extract the "123" using awk.
I thought about awk -F"]" '{ print $1 }' but it doesn't work
Any ideas ? (7 Replies)
hi,
i have a file called file1.txt and it's contents are as below:
file1.txt:
-------
abc,123, thomas
dab,234,muller
gab,456,ram
The lookup file's contents are as below:
lookup.txt
----------
abc|japan
dcd|US
dab|china
gab|brazil (3 Replies)
Line from input file
a : b : c " d " e " f : g : h " i " j " k " l
output
k b a
Its taking 7th word when " is the delimiter, 2nd and 1st word when : is the delimiter and returning all in one line.... I am on solaris
Thanks..... (1 Reply)
I have a file having lines like:
14: <a="b" val="c"/>
18: <a="x" val="d"/>
54: <a="b" val="c"/>
58: <a="x" val="e"/>
I need to create a file with output:
14
d
54
e
So basically, for every odd line I need 1st word if delimiter is ':' and for every even... (14 Replies)
Hi Folks,
This is the first time I ever encountered this situation
My input file is of this kind
cat input.txt
1 PAIXAF 0 1 1 -9 0 0 0 1 2 0 2 1 2 1
7 PAIXEM 0 7 1 -9 1 0 2 0 1 2 2 1 0 2
9 PAKZXY 0 2 1 -9 2 0 1 1 1 0 1 2 0 1
Till the sixth column (which is -9), I want my columns to... (4 Replies)
What to know the way to count the number of delimiters in each record by ignoring the escape delimiters.
Sample Data:
12345678|ABN\|XYZ MED CHEM PTY. LTD.|C||100.00|22|AB"C\|Corp|"XYZ|CDEF"|
I'm using awk -F'|' '{ print NF-1 }' command to find the number of delimiters. this command... (8 Replies)
I have a file which is separated by delimiter "|", but the prob is one of my column do contain delimiter as description so how can i differentiate it?
PS : the delmiter does have backslash coming before it, if occurring in column
Annual|Beleagured|Desc|Denver... (2 Replies)
Discussion started by: nikhil jain
2 Replies
LEARN ABOUT HPUX
zgrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)
01-27-2011
) to do it.