Hello, I have a file, and one column has both positive and negative numbers. Does anyone know how I can calculate the total of all the values (i.e, +ve and -ve).
eg:
col1 col2 col3
data 23 data
data 76 data
data -30 data
Thanks
Khoom (1 Reply)
i know how to add two numbers using expr,
but if i have a file with hundreds of numbers, how do i add them all together, without typing them all one by one?
for example, file.txt contains
4
5
6
7
how can i give a command to add them, without typing
$ expr `4 + 5 + 6 + 7` (7 Replies)
Hi this is quite a simple question... I am new to LINUX/UNIX and so I am just trying to create a very basic program. The idea is that when the user runs the program (from the shell) they enter 3 values and the program will add them up:
"./sum 23 5 1
29"
my code for this program is as follows:
... (4 Replies)
Hi
I figured how to add my list of numbers. However how do I count so that after a certain number it lists the line.
Example:
12 test1
46 test2
195 test3
174 test4
634 test5
185 test6
94 test7
So basically add the numbers and when the addition reaches 300 or less
print the... (8 Replies)
I have a file which has following contents which I want to add up.
28170.24
28170.24
28170.24
28170.24
28170.24
28170.24
28170.24
28170.24
28170.24
28170.24
28170.24
28170.24
28170.24
28170.24
139038.72
139038.72
139038.72
139038.72 (5 Replies)
Hello. Trying to add a column of numbers and combine the 1st and 2nd fields as uniq with the new total.
This works to add the numbers but can't figure an easy was to combine the 1st and 2nd column as the list is very long. awk '{s+=$3} END {print s}'
bird dog 300
bird dog 100
cat clown 200... (1 Reply)
Hi again. Sorry for all the questions — I've tried to do all this myself but I'm just not good enough yet, and the help I've received so far from bartus11 has been absolutely invaluable. Hopefully this will be the last bit of file manipulation I need to do.
I have a file which is formatted as... (4 Replies)
Hi Folks,
I have a file with 2 columns TAB delimited and I want to add '1' to the first column and subtract '-1' from the second column.
What I have tried so far is;
awk -F"\t" '{ $1-=1;$2+=1}1' OFS='\t' file
File
0623 0623
0624 0624
0643 0643
1059 1037
1037 1037
1038 1038... (2 Replies)
Hi All,
Could you please help me on this requirement.
File data:
A
A
A
B
B
B
i need the output like
A1
A2
A3
B1 (3 Replies)
Discussion started by: bmk123
3 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)