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Top Forums Shell Programming and Scripting how to test input variable is a string in a select loop Post 302490494 by Chubler_XL on Monday 24th of January 2011 11:38:16 PM
Old 01-25-2011
The variable REPLY is set by the select command and is what the user typed to the prompt. If REPLY is a valid selection select will assign your variable (file) to the value that equates to the user typed selection.

So for select fruit in apple pear peach if user types 1 you get REPLY=1 fruit="apple" if user types Q you get REPLY=Q fruit="" so you can see fruit will always be one of the valid choices or blank where REPLY is just what the user typed.


The code I posted works fine for me in both bash and ksh, please check you have copied the code as shown and if your sure it's fine can you supply some info on the shell and OS you are using.
 

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ARRAY_POP(3)								 1							      ARRAY_POP(3)

array_pop - Pop the element off the end of array

SYNOPSIS
mixed array_pop (array &$array) DESCRIPTION
array_pop(3) pops and returns the last value of the $array, shortening the $array by one element. Note This function will reset(3) the array pointer of the input array after use. PARAMETERS
o $array - The array to get the value from. RETURN VALUES
Returns the last value of $array. If $array is empty (or is not an array), NULL will be returned. ERRORS
/EXCEPTIONS This function will produce an error of level E_WARNING when called on a non-array. EXAMPLES
Example #1 array_pop(3) example <?php $stack = array("orange", "banana", "apple", "raspberry"); $fruit = array_pop($stack); print_r($stack); ?> After this, $stack will have only 3 elements: Array ( [0] => orange [1] => banana [2] => apple ) and raspberry will be assigned to $fruit. SEE ALSO
array_push(3), array_shift(3), array_unshift(3). PHP Documentation Group ARRAY_POP(3)
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