HI all
I'm trying to write an awk script to print the min and max value in a range(s) contained in another file - the range values are in $2
EG
114,7964,1,y,y,n
114,7965,1,y,y,n
114,7966,1,y,y,n
114,7967,1,y,y,n
114,7969,1,y,y,n
114,7970,1,y,y,n
114,7971,1,y,y,n
114,7972,1,y,y,n... (3 Replies)
Hi All,
I am trying to extract lines bsed on pattern matching../mp straight-flow/
Extracted output should be saved in meta_string , but the code is not working in that manner,saving repeated lines. can anyone please suggest where am i going wrong.
/mp straight-flow/ {... (6 Replies)
How would I pass awk output to a perl variable?
For example, I want to save the value in the 4th column into the variable called test. My best guess is something as follow, but I am sure this isn't correct.
$test = system("awk '/NUMBER/{print \$4}' $_"); (8 Replies)
Hi,
I am trying to use AWK to do some editing and formating of large tables of numbers and I am having trouble getting it to work. For brevities sake, I won't show the whole table, but I have a sample set of code:
und$ awk '{($2+0) > 50;print $1}' temp
2000 147
2008 128
2002 100
1999 47... (2 Replies)
# foreach sub ( sub001 )
sub=sub001
cd /mnt/stor/smith/recog/$sub/event_files/timecorrected/
awk '{$1-1.5}' $sub_CR
end
What im trying to do is:
1. open a 1D file that consists of lists of integers in rows a columns
2. subtract 1.5 from each integer in the first column
3. save the file... (1 Reply)
Hello all,
Let's say we have this file :
$ cat inputfile
2
3
4
7
8
11
15
16
17
I'm trying to make a script with awk which gives as output the following : (4 Replies)
Hello guys, I just start trying out AWK and encounter a problem, I try to think a bit but seems my way is incorrect.
I have two input file, with the first file has only one field, the second file has 3 fields, I suppose to do stuffs to them by writing an awk program, kinda sort them out. Since I... (15 Replies)
Hi,
I have a text file, which I am trying to parse.
File contents:
BEG
Id Job1
Id Stage1
1
EN
Id Job2
Id Stage2
BEG
Id2 Job3
Id Stage4
2
EN
I have to process the data in this between every BEG and EN. so I am trying to restrict the range and inside every... (1 Reply)
Dear Unix gurus,
I have sample data organised like this and containing 6 columns (with headers):
label c2 c3 c4 c5 c6
where c2 to c6 are numeric values in columns c2 to 6.
I am trying to create a simple output in a new file containing 3 columns:
label max(c2 c3) max(c4 c5 c6)
... (4 Replies)
Discussion started by: ksennin
4 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)