I have gotten myself totally lost trying to sort this out and just need some help please..
I will have a multiple directories using the following naming convention with an undetermined number of files in each directory.
9780743582094_05of5_Accountable.wav
I need to batch rename all files grabbing the two digit number after the first underscore, and appending it to the end of the file name,with a preceding hyphen, before the extension.
The example: 9780743582094_05of5_Accountable.wav
Would become
9780743582094_05of5_Accountable-05.wav
I know sed or awk could work but I have not been using Linux/Unix for some time and really have burned out trying to remember this. Please show me the way with an explanation. I am using Ubuntu 10.04 and have the rename command available to me.
For those who are going to insist to see some effort on my part, sadly this is all I've got:
The reason i am doing this is to try and use a script that I found to batch convert wav files to .m4b audiobook format, but I first must convert to mp3. If anyone has a better suggestion to accomplish this, I would also love to hear about that. But first, I really need an answer to this sed issue because it is upsetting me.
I would appreciate it if any one can guide me in using awk perhaps sed in extracting some values from a long string.
here is an example.
.......some lines here........
........ aaaa bbbb cccc ddddd eeeee fffff gggg (time:hhhh)........
......some lines here also..........
How can I extract... (2 Replies)
Hi!
I am writing a script handling downloading list of files and I have to check whether file is present locally and if not finished than continue downloading. To do so I have to compare sizes of remote file and local file.
To check remote file size I have to parse something like this:
... (2 Replies)
in shell scripting there is extensive usage of
i> regular expression
ii>sed
iii>awk
can anyone tell me the suitable contexts ...i mean which one is suitable for what kind of operation.
like the reg-exp and sed seems to be doing the same job..i.e pattern matching (1 Reply)
1. The problem statement, all variables and given/known data:
Problem Statement for project:
When an account is created on the CS Unix network, a
public html directory is created in the account's home directory. A default web page is put into that directory.
Some users replace or... (13 Replies)
Hi all,
I have a list that I would like to parse with awk/sed. The list is contains entries such as:
JournalTitle: Biochemistry
JournalTitle: Biochemistry and cell biology = Biochimie et biologie cellulaire
JournalTitle: Biochemistry and experimental biology
JournalTitle: Biochemistry and... (6 Replies)
I have a filename like 1_DATE_3_4.5_888 and I want to modify the date field (ie the last 4 digits ) alone and remove the last field.
Old filename:1_DATE_3_4.5_888
Given date (for eg):120606259532
modified date:120606259899
new filename:1_<modified date>_3.4.5 (14 Replies)
here is what i want to achieve... consider a file contains below contents. the file size is large about 60mb
cat dump.sql
INSERT INTO `table1` (`id`, `action`, `date`, `descrip`, `lastModified`) VALUES (1,'Change','2011-05-05 00:00:00','Account Updated','2012-02-10... (10 Replies)
Dear All,
Can anyone help to remove the , bewteen "" in a string by using sed or awk?
e.g.
input : 1,4,5,"abcdef","we,are,here",4,"help hep"
output:1,4,5,"abcdef","wearehere",4,"help hep"
Thanks,
Mimi (5 Replies)
Sorry for the long/weird title but I'm stuck on a problem I have. I have this XML file:
</member>
<member>
<name>TransactionID</name>
<value><string>123456789123456</string></value>
</member>
<member>
<name>Number</name>
... (9 Replies)
I have a file comp.pkglist which mention package version and release . In 'version change' and 'release change' line there are two versions 'old' and 'new' Version Change: --> Release Change: -->
cat comp.pkglist
Package list: nss-util-devel-3.28.4-1.el6_9.x86_64
Version Change: 3.28.4 -->... (1 Reply)
Discussion started by: Paras Pandey
1 Replies
LEARN ABOUT LINUX
wrap-and-sort
WRAP-AND-SORT(1) General Commands Manual WRAP-AND-SORT(1)NAME
wrap-and-sort - wrap long lines and sort items in Debian packaging files
SYNOPSIS
wrap-and-sort [options]
DESCRIPTION
wrap-and-sort wraps the package lists in Debian control files. By default the lists will only split into multiple lines if the entries are
longer than 80 characters. wrap-and-sort sorts the package lists in Debian control files and all .install files. Beside that wrap-and-sort
removes trailing spaces in these files.
This script should be run in the root of a Debian package tree. It searches for control, control.in, copyright, copyright.in, install, and
*.install in the debian directory.
OPTIONS -h, --help
Show this help message and exit.
-a, --wrap-always
Wrap all package lists in the Debian control file even if the entries are shorter than 80 characters and could fit in one line line.
-s, --short-indent
Only indent wrapped lines by one space (default is in-line with the field name).
-b, --sort-binary-packages
Sort binary package paragraphs by name.
-k, --keep-first
When sorting binary package paragraphs, leave the first one at the top. Unqualified debhelper(7) configuration files are applied to
the first package.
-n, --no-cleanup
Do not remove trailing whitespaces.
-d path, --debian-directory=path
Location of the debian directory (default: ./debian).
-f file, --file=file
Wrap and sort only the specified file. You can specify this parameter multiple times. All supported files will be processed if no
files are specified.
-v, --verbose
Print all files that are touched.
AUTHORS
wrap-and-sort and this manpage have been written by Benjamin Drung <bdrung@debian.org>.
Both are released under the ISC license.
DEBIAN Debian Utilities WRAP-AND-SORT(1)